simple factoring question

[InlineFour]

eg. x^3 + x^2 + x

you can't out a x because of the constant, right? so this would be incorrect, x(x^2 + x 1).

 

[hypn0tik]

Originally posted by: InlineFour
eg. x^3 + x^2 + x

you can't out a x because of the constant, right? so this would be incorrect, x(x^2 + x 1).

Of course you can. That's the factored form.

 

[InlineFour]

Originally posted by: hypn0tik

Originally posted by: InlineFour
eg. x^3 + x^2 + x

you can't out a x because of the constant, right? so this would be incorrect, x(x^2 + x 1).

Of course you can. That's the factored form.

wait, let me rephrase the question. find the roots of x^3 + x^2 + x

can you still factor it into x(x^2 + x 1)?

 

[hypn0tik]

Originally posted by: InlineFour

Originally posted by: hypn0tik

Originally posted by: InlineFour
eg. x^3 + x^2 + x

you can't out a x because of the constant, right? so this would be incorrect, x(x^2 + x 1).

Of course you can. That's the factored form.

wait, let me rephrase the question. find the roots of x^3 + x^2 + x

can you still factor it into x(x^2 + x 1)?

Yes. You can factor it that way. You can also find the roots by setting the expression to 0.

i.e.
x(x^2 + x + 1) = 0

 

[zanieladie]

I agree...factor out the "x." Setting the expression to "0" also works...happy solving! 🙂

 

[tfcmasta97]

Originally posted by: hypn0tik

Originally posted by: InlineFour

Originally posted by: hypn0tik

Originally posted by: InlineFour
eg. x^3 + x^2 + x

you can't out a x because of the constant, right? so this would be incorrect, x(x^2 + x 1).

Of course you can. That's the factored form.

wait, let me rephrase the question. find the roots of x^3 + x^2 + x

can you still factor it into x(x^2 + x 1)?

Yes. You can factor it that way. You can also find the roots by setting the expression to 0.

i.e.
x(x^2 + x + 1) = 0

hypnotik factored it correctly, since you're dividing X by X it leaves a constant of 1

 

[hypn0tik]

Originally posted by: tfcmasta97

Originally posted by: hypn0tik

Originally posted by: InlineFour

Originally posted by: hypn0tik

Originally posted by: InlineFour
eg. x^3 + x^2 + x

you can't out a x because of the constant, right? so this would be incorrect, x(x^2 + x 1).

Of course you can. That's the factored form.

wait, let me rephrase the question. find the roots of x^3 + x^2 + x

can you still factor it into x(x^2 + x 1)?

Yes. You can factor it that way. You can also find the roots by setting the expression to 0.

i.e.
x(x^2 + x + 1) = 0

hypnotik factored it correctly, since you're dividing X by X it leaves a constant of 1

Oh, I assumed that was a typo on his part. Guess I should have pointed that out.