Searching a string in C

[Isocene]

If I have a string that is an email address (blah@place.com) how would I chop it into (place.com) in C?

I used

strcpy(tmp, strchr(tempadr,'@'));

but it gives me @place.com and I dont know how to omit just the first character. Anyone have any ideas?

Mike

 

[Gaunt]

Nevermind... the solution I posted was far too quickly thought out, and won't work. 🙂

Or, actually, it probably will work. 🙂

strchr will return the pointer to the first character you're searching for, in this case @, so just add 1 to it.

This should work, and is what I posted earlier:

strcpy(tmp, strchr(tempadr,'@')+1);

It's been a long day.... 🙂

 

[singh]

strchr() + 1 will do it. But I wouldn't recommend it unless you're 100% sure your input string is well formed (and you've also done the proper string-length checks).

 

[Isocene]

worked great! Thanks!

 

[Descartes]

Personally, I would use a regular expression for this. There are quality regex implementation libraries available, including the one that comes with GNU libc. I believe there is a win32 port for it as well.

[edit]Just to expound... the reason I'd use a regex is for validation; simply parsing it is easy enough.[/edit]

 

[glugglug]

Originally posted by: singh
strchr() + 1 will do it. But I wouldn't recommend it unless you're 100% sure your input string is well formed (and you've also done the proper string-length checks).

Easy to tell.

strchr will return NULL if it finds the end of the string (determined by '\0' char which all your strings should end with) before it finds a '@'.

 

[bsobel]

strchr will return NULL if it finds the end of the string (determined by '\0' char which all your strings should end with) before it finds a '@'.

Yes it's easy to tell, but the posted code "strcpy(tmp, strchr(tempadr,'@')+1);" doesn't even make an attempt 😉

Bill

 

[Gaunt]

Ya, I know... I felt a little bad for suggesting something that might be a tad unsafe...

It was a quick post just to get him going with whatever he was doing... in the future I'll take a bit more time to explain. 🙂