Real quick integration help

[RESmonkey]

Integrating 1/((y-1)^2). I turned it into (y-1)^-2 , did you U substitution:

u = (Y-1)^-1
du = -(y-1)^-2 * y'

Problem is, what do I do with the y' ?

 

[JohnCU]

Originally posted by: RESmonkey
Integrating 1/((y-1)^2). I turned it into (y-1)^-2 , did you U substitution:

u = (Y-1)^-1
du = -(y-1)^-2 * y'

Problem is, what do I do with the y' ?

solve dy in terms of du and insert back

wait why don't you substitute in u = y-1, du = dy, and then integrate u^-2?

 

[RESmonkey]

Epic Thanks!

EDIT = To be more specific, yeah, you're right. u = y-1 would be the best/correct way.