Quick Math Question

amol

Lifer
Jul 8, 2001
11,680
3
81
If x^0 = 1, what are the restrictions on x?

(base x with exponent 0)
 

Legendary

Diamond Member
Jan 22, 2002
7,019
1
0
-infinity < x < infinity ??
Don't trust me that's a guess and I'm drunk.
 

amol

Lifer
Jul 8, 2001
11,680
3
81
i thought that 1^0 doesnt equal 1 since 1^1=1

and that there are 3 different answers for 0^0 . . . some say it's 1, others say 0, others say it is undefined
 

czech09

Diamond Member
Nov 13, 2004
8,990
0
76
Originally posted by: BEL6772
Just a guess ... real numbers?

No E^0 is 1 as well. I don't know about 0 for sure. I'd look it up but I'm 99.9% sure you won't need that anyways I've never done 0^1
 

BigJ

Lifer
Nov 18, 2001
21,330
1
81
Originally posted by: Amol
i thought that 1^0 doesnt equal 1 since 1^1=1

and that there are 3 different answers for 0^0 . . . some say it's 1, others say 0, others say it is undefined

I've never seen someone say that 0^0 = 0. I have seen people say that it is 1, indeterminate, or undefined.

1^0 is definitely 1.
 

amol

Lifer
Jul 8, 2001
11,680
3
81
my idea is that 0^0 is undefined since :

0^5 = 0

so 0^5/0^5 = 0/0 = undefined
 

czech09

Diamond Member
Nov 13, 2004
8,990
0
76
Originally posted by: Amol
ahh, screw it, i'll just look in the back of the book :p

That shall explain your 26 ppd...you wasted 10 mins of my precious time. What class is this supposed to be for anyways. (Don't tell me it's for some high school Algebra course or I'll slap you long distance)...
 

chuckywang

Lifer
Jan 12, 2004
20,133
1
0
x=all reals except 0.

0^0 is undefined. anybody who says otherwise doesn't know what they're talking about.