Quick math help: logarithms

[TNTrulez]

Is n*log(a/b) = log(a/b)^n?

 

[TNTrulez]

Also how can i combine -1/6log(x/y) -1/2log(b/z) to one single logarithm?

 

[Syringer]

Originally posted by: TNTrulez
Is n*log(x/b) = log(a/b)^n?

Do you mean n*lob(a/b) = log(a/b)^n?

And, if you mean n*lob(a/b) = log((a/b)^n), instead of (log(a/b))^n

then that's right.

 

[TNTrulez]

Originally posted by: Syringer

Originally posted by: TNTrulez
Is n*log(x/b) = log(a/b)^n?

Do you mean n*lob(a/b) = log(a/b)^n?

And, if you mean n*lob(a/b) = log((a/b)^n), instead of (log(a/b))^n

then that's right.

Thanks. Also, let say that 2x=a

Then how would I substitute x for a in log(a)?

Would it be log(x^2)?

 

[Syringer]

No it'd just be log (2x).

If you were substituting in a = x^2 though, then it could either be log(x^2) or 2 log(x).