Question about the ti-89, can't find a special type of square root =P

etalns

Diamond Member
Dec 20, 2001
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Hey all, been looking for the cubed square root for the last few days on my ti-89

On a ti-83 you'd just go under math --> then you can find itthere

it is like a normal square root sign, except it has an exponent 3 before it. You use it to root cubes etc.

Would appreciate it a ton if anyone can help me out.
 

Chaotic42

Lifer
Jun 15, 2001
34,349
1,524
126
My Ti-86 has an "X-root" function. It's a square root symbol with an x in the corner. You'd hit

3
(x root thing)
8
Enter

and get 2.

Maybe the 89 has something similar?
 

etalns

Diamond Member
Dec 20, 2001
6,513
1
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Originally posted by: Rahminator
The cubed square root is under the any key.

In my complete and utter stupor of being up for over 36 hours now....I actually looked for the any key for about 20-30 seconds...then it hit me.

grr!
 

etalns

Diamond Member
Dec 20, 2001
6,513
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I've looked, and it says there is an x/root function somewhere in the calculator. Now to find it.

This is worse than Where's Waldo =(
 

Rahminator

Senior member
Oct 11, 2001
726
0
0
Originally posted by: Qosis
Originally posted by: Rahminator
The cubed square root is under the any key.

In my complete and utter stupor of being up for over 36 hours now....I actually looked for the any key for about 20-30 seconds...then it hit me.

grr!

When it hit you, did it also make you realize that there's no such thing as a cubed square root? ;)
 

Yomicron

Golden Member
Mar 5, 2002
1,735
1
81
As far as I know, the TI89 doesn not have that function built in.

You have to do x^(1/3)

but if you want a xroot command do this:

Goto APPS -> Program Editor -> New...
Set type to Function
Name it xrt (you can name it anything, but its best to make it short)
where it says xrt() make it say xrt(b,r)
under FUNC type b^(1/r)
press HOME

Usage example:
cubed root of 8

type xrt(8,3) and you should get 2 as the answer

 

Yomicron

Golden Member
Mar 5, 2002
1,735
1
81
Currently here is what my program looks like

xrt(b,r)
Prgm
b^(1/r)
EndPrgm

Now, where did I go wrong on that one? I dont see anywhere that it says function to put the second section under, or do I input that myself.

when you are at the new program dialog box, select Function from the type menu. ( the default is Program )