Q6600 OC theory (possible general theory for all CPU's)?

imported_Shaq

Senior member
Sep 24, 2004
731
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okay...straight to the point. I have a Q6600 and the voltage range is 1.1-1.35 with some sites a little different than that range. I have a "bad" VID on my chip: 1.325 and I've seen ranges of 1.15-1.325 for VID. Can I assume that the voltage range is for stock running across a range of VID's and not the absolute maximum that the chip can handle while still lasting a "full" lifetime?

For instance, it is debated on several sites that lower VID chips produce more heat at lower voltages than a higher VID chip ie. a 1.2 VID cpu at 1.35v will run a lot hotter than a cpu with a VID of 1.35 at 1.35v. So having said that, it seems that the voltage range on the cpu is not important when OC'ing as much as being some "absolute" above your VID ie. .05-.3v above VID.

I surmise that it is based on temps as much as voltage since cpu's with higher VID's are not as efficient as lower VID chips. If you received a cpu with a high VID you would have to say "I'm already at the top of the voltage range so I guess I got screwed-I can't OC". And if you got a VID chip of 1.15 you would say "wow, now I can OC to 1.35v and be a 1337 OC'er Woot!".

The lower VID is still technically under warranty I would assume unless you can't raise the voltage at all? Does this make any sense to anybody or am is my mind just too active/too bored today?
 

PlasmaBomb

Lifer
Nov 19, 2004
11,636
2
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Originally posted by: Markbnj
Probably belongs in CPU forum.

Agreed

First off if you overclock you void your warranty. It doesn't matter if you touch the voltage or not *sorry*.

Secondly P = FIV^2

So if you have a 1.15v Q6600 and a 1.35v Q6600 the 1.35v chip will dissipate more heat.