plz help with oscillation problem...

Omegachi

Diamond Member
Mar 27, 2001
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An object on a horizontal spring oscillates with a period of 4.5s. If the object is suspended from the spring vertically, by how much is the spring stretched from its natural length when the object is in equailibrium?
 

gopunk

Lifer
Jul 7, 2001
29,239
2
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i'm just learning this stuff now (well, for the second time :p)... don't you need at least the spring constant or the mass though?
 

thEnEuRoMancER

Golden Member
Oct 30, 2000
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Well, let's see.

omega = (k/m)^(1/2)

where k is spring constant and m is mass

furthermore

omega = 2*pi*1/t0

where t0 is the period and pi=3.14...

The elongation of spring in equlibrium is

s = m*g/k = (m/k)*g

where g = 9.81

Combine the equations together to determine s. You don't need the actual values of k and m.
 

gopunk

Lifer
Jul 7, 2001
29,239
2
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<< ummmm..... 6.5 w/ a 2.8098 coefficient >>



wouldn't that be 18 something? can you show us how you did that?
 

gopunk

Lifer
Jul 7, 2001
29,239
2
0
Combine the equations together to determine s. You don't need the actual values of k and m.

ah i see... so 5.0268 m?