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Please help my RIGHT ANGLE.

B

Bob151

Senior member
I am over 20 years removed, I just forget how to solve for this equation. I'm trying to finish a closet redo, I need to cut some wood to the correct angles.

My triangle is a right angle triangle, a=11 b=16, so c=~19.4.

What I can't get are the 2 inside anlges. I forget this part.

It seems that according to google results, I sin(angle)=b/c. All the examples I have found, they solve for the b or the c and actually provide the angle.

I'm so removed from geometry (I liked it in school and did well, I just completely forget).

I don't know how to solve this when my variable needs to be sin'ed. Does it go accsin, cosin, help me with this puzzle please. I'm sure there are hundreds of you here that know.

Please post haste.

Thanks.
 
sin angle = opposite over hypotenuse
cos angle = adjacent over hypotenuse

To find the angle you will have to arcsin/arccos the measurements.

here, i'll do it for you.
A angle = 34.5
B angle = 55.6 degrees

For clarification, the angle will be opposite of the indicated side.
 
Originally posted by: QurazyQuisp
Soh Cah Toa

Sin: opposite over hypotenuse
Cos: adjacent over hypotenuse
Tan: opposite over adjacent
Click to expand...
Aye,
Some Old Hippe Caught Another Hippie Tripping On Acid
 
The sine of an angle is equal to (the length of the side opposite the angle) divided by (the length of the hypotenuse).
The cosine of an angle is equal to (the length of the side adjacent to the angle that is not the hypotenuse) divided by (the length of the hypotenuse).
The tangent of an angle is equal to (the length of the side opposite the angle) divided by (the length of the side adjacent to the angle).

Whichever one you need to use, plug in the side lengths and then use the inverse function (arcsin or sin^-1 for sine, etc.) to find the angle.
 
Originally posted by: deadlyapp
sin angle = opposite over hypotenuse
cos angle = adjacent over hypotenuse

To find the angle you will have to arcsin/arccos the measurements.

here, i'll do it for you.
A angle = 34.5
B angle = 55.6 degrees

For clarification, the angle will be opposite of the indicated side.
Click to expand...

Thanks deadlyapp and everyone else. I knew they answer could be found here.

But for my future use, where is the arcsine on the windows calc. I see sin, cos, tan.... I'm sure that if they went through the trouble to add that, they would be complete on the arc functions too, right?

 
Originally posted by: Bob151
Originally posted by: deadlyapp
sin angle = opposite over hypotenuse
cos angle = adjacent over hypotenuse

To find the angle you will have to arcsin/arccos the measurements.

here, i'll do it for you.
A angle = 34.5
B angle = 55.6 degrees

For clarification, the angle will be opposite of the indicated side.
Click to expand...

Thanks deadlyapp and everyone else. I knew they answer could be found here.

But for my future use, where is the arcsine on the windows calc. I see sin, cos, tan.... I'm sure that if they went through the trouble to add that, they would be complete on the arc functions too, right?
Click to expand...

Inverse sin, cos and tan.
 
Originally posted by: Bob151
Originally posted by: deadlyapp
sin angle = opposite over hypotenuse
cos angle = adjacent over hypotenuse

To find the angle you will have to arcsin/arccos the measurements.

here, i'll do it for you.
A angle = 34.5
B angle = 55.6 degrees

For clarification, the angle will be opposite of the indicated side.
Click to expand...

Thanks deadlyapp and everyone else. I knew they answer could be found here.

But for my future use, where is the arcsine on the windows calc. I see sin, cos, tan.... I'm sure that if they went through the trouble to add that, they would be complete on the arc functions too, right?
Click to expand...
There's a checkbox labeled Inv. Click that and the functions should become inverses... I think.
 
Originally posted by: Howard
There's a checkbox labeled Inv. Click that and the functions should become inverses... I think.
Click to expand...

Ah, yes.

Thanks, now I see how to get the answer for myself now with MS' calc.

Got the project done.

Thanks, to all who helped.
 
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