• We’re currently investigating an issue related to the forum theme and styling that is impacting page layout and visual formatting. The problem has been identified, and we are actively working on a resolution. There is no impact to user data or functionality, this is strictly a front-end display issue. We’ll post an update once the fix has been deployed. Thanks for your patience while we get this sorted.

Please help identify this MB component.

drteming

Senior member
My spare rig died, and I initially traced it to a power supply failure (the power good signal was bad). After swapping in a good power supply, the board booted up. However looking at the motherboard more closely, I noticed that this component (circled in red) had blown out (the picture is a stock photo). It looks easy to replace. Can anyone tell me what it is? Thanks. The board is a Gigabyte GA-MA790X-UD4P

11197075263_d42d5aef5c_o_d.jpg
 
do the mobo works.this is related to the sys.fan or f-usb.and it don't look like it burned.
 
Last edited:
I think I figured it out. It's a 16 ohm SMD resistor related to the front USB headers. I'll have to measure the size to determine the wattage rating. The picture I posted was a stock photo showing the original condition.

The question now is: did the power supply failure have anything to do with the resistor burning out, or the other way around, or are they unrelated?
 
That device's purpose is to act as a fuse for the USB ports at F_USB1. It is meant to burn out to protect the rest of the motherboard (or anything connected via USB for that matter).

I would say it is unlikely that the fuse killed the power supply, but it is plausible that a dying power supply can behave out of specifications in its death throes and blow the fuse.

The consequences of it being blown is that F_USB1 won't work. If you can get by without it, you won't notice the difference.

Regarding the size of the fuse (typically measured in amps rather than watts): Have a look at an Intel paper on the topic. It should provide some guidance in selecting the appropriate value. If too low it will burn out during use prematurely. If too high it will fail in its purpose of protection.
 
Back
Top