I know the secret to the 3 rows one, 4th row is messing me up, but I don't think you can win the 3 rows one because he forces you to take first.
in case it helps any, the 3 rows one works on this principle, if you leave your opponent with a 3-2-1 formation of 0-x-x formation, you win. Here's why, in the base case of x-x-0, no matter how much you take from one column, if he matches you in the other column, you return to x-x-0. The exception is if you leave 1 bead left, then he just takes all of the other column, and you lose. The 3-2-1 works in that if you take the one, he takes 1 from 3 and leaves an x-x-0. If you take from the 2, he takes 2 from the 3 column leaving 1-1-1, which is losing for you. If you take from the 3 column, he takes the non-matching column left from the 3 and leaves you with 0-x-x.
if you look at the 3 row case, no matter how much you take from any column, he can either leave you with an x-x-0 or 3-2-1. You could win if it'd let you take zero beads tho.