physics question

UCBPride

Senior member
Feb 20, 2001
383
0
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if 9g of water is placed into a 2L pressure cooker and heated to 500c, what is the pressure inside the container?

PV=nRT, but how do i get n??

n=m/M (mass / mole)

or should i ask, how do i get the molar mass? wtf is molar mass anyway


sigh, i wish i was smart :(
 

OS

Lifer
Oct 11, 1999
15,581
1
76


<< wtf is molar mass anyway >>



Molar mass is how much one mole of the given molecule weighs.
 

notfred

Lifer
Feb 12, 2001
38,241
4
0
water = H20

molar mass of water is like 18 (roughly)

Add up the atomic weight of the 2 hydrogens and the oxygen. That number in grams is your weight/mole of water.



*Disclaimer - it's been several years since I took chemistry. and this is a chemistry question, not physics (at least where I went to school)
 

Rakkis

Senior member
Apr 24, 2000
841
1
0
once you have your molar mass (i.e. ~ 18 grams/mole)

you multiply your mass (9g) times (1 mole/ 18 grams) and you get n=0.5 mole.
 

Ameesh

Lifer
Apr 3, 2001
23,686
1
0


<< sigh, i wish i was smart >>




your not dumb just lazy, you could have easily look up what molar mass is.
 

UCBPride

Senior member
Feb 20, 2001
383
0
0
wow you guys rock :)

heres another question for ya. what am i doing wrong here: P= nRT/ v where R = .0821, T=773.15 K, n=.5, V = 2 comes out to 15.8 but the answer is 16.1 :confused:
 

monto

Platinum Member
Oct 12, 1999
2,047
0
0
i tried using the slightly more exact R value of 0.8206, but nada, also tried O and H molecular mass at 6 significant digits, but still nada, so i'm guessing the difference in the answer is due to something perhaps in the instructions, ie are you to assume all 9g of water is turned into water vapor, are you to assume the water vapor is an ideal gas? (cause realistically it's far from)...worse comes to worse, just round your answer to 16atm :p

btw, is this physics 8A?
 

jamesave

Golden Member
Aug 27, 2000
1,610
0
76
If you're not assuming it's ideal, then it's PV=nRTz where z is the compression factor..


EDIT: The sentence above maybe wrong. Since this is water vapor, you may need to llok at super steam chart..