Physics Question

[audi]

sorry guys, I have just not been able to work this physics question out. here's the problem:

Two small objects, A and B, are fixed in place and separated by 2.00 cm in a vacuum. Object A has a charge of +1.00 µC, and object B has a charge of -1.00 µC. How many electrons must be removed from A and put onto B to make the electrostatic force that acts on each object an attractive force whose magnitude is 45.0N?


I tried using Coulomb's Law: F = (KQ1Q2)/(r^2)

Knowing that the charge of the electron is 1.6 * 10^-19 and K is a constant of 8.99 * 10 ^ 9 I tried plugging the following in.

45=((8.99*10 ^ 9)(1*10^-6 + (1.6*10^-19)x)^2)/((.02)^2)

I solved this for X and got 7.95 * 10 ^ 22 when the back of the book says 2.6 * 10^12.

Could you please tell me where I'm going wrong, thanks.

 

[FoBoT]

eleventy billion? 😕

 

[Colt45]

42

 

[Legendary]

Edit: I'm an idiot - one sec - I learned this a long time ago and I might be able to remember it.

 

[audi]

anybody, i know this is a quick bump, but these forums move quick

 

[dighn]

your euqation looks right to me and from it i get the book answer of 2.59 x 10^12

u just did the calc wrong

 

[mAdMaLuDaWg]

nm

 

[BigJ]

Originally posted by: dighn
your euqation looks right to me and from it i get the book answer of 2.59 x 10^12

u just did the calc wrong

 

[audi]

Originally posted by: dighn
your euqation looks right to me and from it i get the book answer of 2.59 x 10^12

u just did the calc wrong

wow you're right, I did it 3 different times and got the wrong answer each time. 🙁 thanks for the help

 

[gabemcg]

do ur own hom3werk