sorry guys, I have just not been able to work this physics question out. here's the problem:
Two small objects, A and B, are fixed in place and separated by 2.00 cm in a vacuum. Object A has a charge of +1.00 µC, and object B has a charge of -1.00 µC. How many electrons must be removed from A and put onto B to make the electrostatic force that acts on each object an attractive force whose magnitude is 45.0N?
I tried using Coulomb's Law: F = (KQ1Q2)/(r^2)
Knowing that the charge of the electron is 1.6 * 10^-19 and K is a constant of 8.99 * 10 ^ 9 I tried plugging the following in.
45=((8.99*10 ^ 9)(1*10^-6 + (1.6*10^-19)x)^2)/((.02)^2)
I solved this for X and got 7.95 * 10 ^ 22 when the back of the book says 2.6 * 10^12.
Could you please tell me where I'm going wrong, thanks.
Two small objects, A and B, are fixed in place and separated by 2.00 cm in a vacuum. Object A has a charge of +1.00 µC, and object B has a charge of -1.00 µC. How many electrons must be removed from A and put onto B to make the electrostatic force that acts on each object an attractive force whose magnitude is 45.0N?
I tried using Coulomb's Law: F = (KQ1Q2)/(r^2)
Knowing that the charge of the electron is 1.6 * 10^-19 and K is a constant of 8.99 * 10 ^ 9 I tried plugging the following in.
45=((8.99*10 ^ 9)(1*10^-6 + (1.6*10^-19)x)^2)/((.02)^2)
I solved this for X and got 7.95 * 10 ^ 22 when the back of the book says 2.6 * 10^12.
Could you please tell me where I'm going wrong, thanks.
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