• We’re currently investigating an issue related to the forum theme and styling that is impacting page layout and visual formatting. The problem has been identified, and we are actively working on a resolution. There is no impact to user data or functionality, this is strictly a front-end display issue. We’ll post an update once the fix has been deployed. Thanks for your patience while we get this sorted.

Physics Problem

saahmed

Golden Member
A horizontal force of magnitude 49.7 N pushes a block of mass 3.69 kg across a floor where the coefficient of kinetic friction is 0.561. (a) How much work is done by that applied force on the block-floor system when the block slides through a displacement of 2.66 m across the floor? (b) During that displacement, the thermal energy of the block increases by 38.9 J. What is the increase in thermal energy of the floor? (c) What is the increase in the kinetic energy of the block?

I can get A easy, W=Fxd, and I can get C easily after I get the total thermal energy, just the sum must equal W. But, how do I get the increase in the thermal energy of the floor (part B)?

EDIT: Help setting this one up would be great too.

Tarzan, who weighs 720 N, swings from a cliff at the end of a convenient vine that is 22 m long (Fig. 8-37). From the top of the cliff to the bottom of the swing, he descends by 3.1 m. The vine will break if the force on it exceeds 1260 N. What would the greatest force on the vine be during the swing?

I know it has something to do with potential energy=mg(change in y). But there are other factors I think. Does centripetal acceleration have anything to do with it?
 
the increase in total thermal energy should be the energy lost to friction. So do the total Joules lost in friction minus the thermal energy gained by the block to get what's left over.
 
Originally posted by: drinkmorejava
the increase in total thermal energy should be the energy lost to friction. So do the total Joules lost in friction minus the thermal energy gained by the block to get what's left over.


Hmm. that sounds right, but it doesnt seem to be working. Maybe I am using the wrong equation. I thought it was just normal force x coefficient of friction. So 9.8x.561 right? But that doesnt seem right. Do you happen to know the equation I need to use?
 
Originally posted by: drinkmorejava
the increase in total thermal energy should be the energy lost to friction. So do the total Joules lost in friction minus the thermal energy gained by the block to get what's left over.

I agree with the above. If you have total thermal energy gained, the subtract the component that went to the block and everything else should be in the floor.
 
Originally posted by: saahmed
Originally posted by: drinkmorejava
the increase in total thermal energy should be the energy lost to friction. So do the total Joules lost in friction minus the thermal energy gained by the block to get what's left over.


Hmm. that sounds right, but it doesnt seem to be working. Maybe I am using the wrong equation. I thought it was just normal force x coefficient of friction. So 9.8x.561 right? But that doesnt seem right. Do you happen to know the equation I need to use?

multiply by the mass
 
Originally posted by: saahmed
Originally posted by: drinkmorejava
the increase in total thermal energy should be the energy lost to friction. So do the total Joules lost in friction minus the thermal energy gained by the block to get what's left over.


Hmm. that sounds right, but it doesnt seem to be working. Maybe I am using the wrong equation. I thought it was just normal force x coefficient of friction. So 9.8x.561 right? But that doesnt seem right. Do you happen to know the equation I need to use?

So that's the equation for frictional force. So what did you do next to get thermal energy?
 
Originally posted by: TuxDave
Originally posted by: saahmed
Originally posted by: drinkmorejava
the increase in total thermal energy should be the energy lost to friction. So do the total Joules lost in friction minus the thermal energy gained by the block to get what's left over.


Hmm. that sounds right, but it doesnt seem to be working. Maybe I am using the wrong equation. I thought it was just normal force x coefficient of friction. So 9.8x.561 right? But that doesnt seem right. Do you happen to know the equation I need to use?

So that's the equation for frictional force. So what did you do next to get thermal energy?


Well I need to get the total frictional force I think. 3.69*9.8*.561= 20.28. Is that the correct way to get the total frictional force? That doesnt seem high enough.
 
Originally posted by: saahmed
Originally posted by: TuxDave
Originally posted by: saahmed
Originally posted by: drinkmorejava
the increase in total thermal energy should be the energy lost to friction. So do the total Joules lost in friction minus the thermal energy gained by the block to get what's left over.


Hmm. that sounds right, but it doesnt seem to be working. Maybe I am using the wrong equation. I thought it was just normal force x coefficient of friction. So 9.8x.561 right? But that doesnt seem right. Do you happen to know the equation I need to use?

So that's the equation for frictional force. So what did you do next to get thermal energy?


Well I need to get the total frictional force I think. 3.69*9.8*.561= 20.28. Is that the correct way to get the total frictional force? That doesnt seem high enough.

Doh, sorry for not responding earlier. But anyways, that equation is correct. 20.28N. So the amount of energy being converted into thermal energy will be 20.28N x distance. (w=fxd)
 
Originally posted by: TuxDave
Originally posted by: saahmed
Originally posted by: TuxDave
Originally posted by: saahmed
Originally posted by: drinkmorejava
the increase in total thermal energy should be the energy lost to friction. So do the total Joules lost in friction minus the thermal energy gained by the block to get what's left over.


Hmm. that sounds right, but it doesnt seem to be working. Maybe I am using the wrong equation. I thought it was just normal force x coefficient of friction. So 9.8x.561 right? But that doesnt seem right. Do you happen to know the equation I need to use?

So that's the equation for frictional force. So what did you do next to get thermal energy?


Well I need to get the total frictional force I think. 3.69*9.8*.561= 20.28. Is that the correct way to get the total frictional force? That doesnt seem high enough.

Doh, sorry for not responding earlier. But anyways, that equation is correct. 20.28N. So the amount of energy being converted into thermal energy will be 20.28N x distance. (w=fxd)


Oh..duh. That makes sense. Thanks for helping.
 
Back
Top