Discrete LEDs usually have 1 lead longer than the other. The longer lead is the anode and you connect it to the + power lead. In a computer, you usually have 2 different DC voltage sources, 5 and 12V. Most LEDs like this are designed to run at .02 A or 20 mA. You've already stated that the LED is a 3.5V drop. I've already computed this out for you and if you use the 5V source, then you need a resistor that is 75 Ohms or greater. I think the closest thing you will find is 77 Ohms. You want the closest resistor to that value without GOING UNDER. If you connect it to 12V, you are going to need a 425 Ohm resistor. Once again, the closest value to that without GOING UNDER. If you go under, you will overpower the LED and cause it to burn out in a much shorter time. Back figuring the power draw of the resistors, you will need to find resistors that can handle 1/4 W of power. These are very easy to find and are cheap. You can find them at a radio shack near you...
BTW the 75 Ohm resistor only uses .03W and the 425 Ohm resistor uses .17W....well under the .25W handling capacity of these tiny resistors.