One more probability Question from me

[Cha0s]

Roll a fair die twice and find the probability of at least one 4
here's what i did:

P(A) = |A|/|O| = (6C1*6C0+6C1*6C1)/(12C2)
And i get the answer as 42/66=7/11 and the real answer is 5/36
what did I do wrong?

 

[TheLonelyPhoenix]

Please learn to do your own homework, this is getting ridiculous.

 

[Ryan]

What is the probability that this thread will piss people off with the annoying Ascii characters?

 

[rudeguy]

47

 

[Drakkon]

nevermind....jump on the badnwagaon and say do ur own hw 😀

 

[bret]

what the fik?

 

[MrX82]

answer is 11/36. rolling a fair dice twice probabilistically speaking is the same as rolling a pair of dice.

you want the following outcomes: (1,4) (2,4) (3,4) (4,4) (5,4) (6,4) and (4,1) (4,2) (4,3) (4, 5) (4,6). out of 36 possible outcomes.

 

[Semidevil]

just write out all the possible outcomes for the dice, and count....

 

[DaWhim]

dude, you are asking question on basic probability? that's the first chapter of statistics. way to go, do you own hw