One more Physics question...

[johnjohn320]

Last one for awhile, I swear. I'm gonna work out something so I can understand this stuff better.

OK, you dont even need the problem. All you need to know is I have:

horiz accel: 0
vertical accel: -9.8m/s^2

horiz vi=31.9
vertical vi=10.35

Now I need to find either time or distance (once I find one I can find the other). I know there's something where I have to solve an equation in terms of an unknown, then plug that into something else?

 

[Torghn]

kinematic equations:
d=vi*t+(1/2)*a*t^2
vf^2=vi^2=2*a*d
vf=vi+a*t
d=((vi+vf)/2)*t

You'll need two sets of equstions, one for vertical and one for horizontal.

 

[mugs]

Time or distance until what? Until it hits the ground? Assuming it's starting at ground level? I'm not really sure what you're looking for there.

 

[Torghn]

Originally posted by: mugsywwiii
Time or distance until what? Until it hits the ground? Assuming it's starting at ground level? I'm not really sure what you're looking for there.

He didn't give us the entiere problem. Hence he didn't get a compleat solution.

 

[Yossarian]

This is the same as the problem you posted last night.

 

[JosephSaint]

Yeahhh