- Dec 9, 2000
- 16,528
- 4
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y^2(y^2 - 4) = x^2(x^2 - 5)
Take the derivative of both sides...
(y^2)(2y) + (2yy')(y^2 - 4) = (x^2)(2x) + (2x)(x^2 - 5)
2y^3 + 2y^3y' - 8yy' = 4x^3 - 10
I think this is where I'm messing up, cause after I finish working this, I get a final answer but my Ti-89 says that it's the wrong answer...
Should be 2y^3y' twice. oops.
Take the derivative of both sides...
(y^2)(2y) + (2yy')(y^2 - 4) = (x^2)(2x) + (2x)(x^2 - 5)
2y^3 + 2y^3y' - 8yy' = 4x^3 - 10
I think this is where I'm messing up, cause after I finish working this, I get a final answer but my Ti-89 says that it's the wrong answer...
Should be 2y^3y' twice. oops.