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Need uber chemist to calculate the limiting reagent

iLoveDivX

Banned
The chemical equation is (C7H6O)2 + C3H6O ========> C17H14O + H2O + OH + H

Molecular weight of (C7H6O)2 is 106.13 grams
Molecular weight of C3H6O is 58.08 grams

I used .212 grams of (C7H6O)2
and .058 grams of C3H6O

I need to find which one is the limiting reagent. I can normally do this but forgot what to do when the chemical equation uses two moles of a certain reactant [ie (C7H6O)2]. do i need to divide my answer by two or multiply? thanks
 
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2:1 ratio of first reactant to second reactant. Limiting reagent is second reactant.

Please note that this is a shortened version. Actually calculations may result in a different answer.😉
 
Originally posted by: iLoveDivX
The chemical equation is (C7H6O)2 + C3H6O ========> C17H14O + H2O + OH + H

Molecular weight of (C7H6O)2 is 106.13 grams
Molecular weight of C3H6O is 58.08 grams

I used .212 grams of (C7H6O)2
and .058 grams of C3H6O

I need to find which one is the limiting reagent. I can normally do this but forgot what to do when the chemical equation uses two moles of a certain reactant [ie (C7H6O)2]. do i need to divide my answer by two or multiply? thanks

Figure out the molar equivalents of each of the reactants. The one with the lower equivalent value is the limiting reagent.
 
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