Need some quick physics help~

TecHNooB

Diamond Member
Sep 10, 2005
7,458
1
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Here's the question, much simpler from last time:

A mass of 0.081 kg hangs from a vertical spring in the lab room. You pull down on the mass and throw it vertically downward. The speed of the mass just after leaving your hand is 4.20 m/s.

(a) While the mass moves downward a distance of 0.09 m, how much work was done on the mass by the Earth? Include the appropriate sign.

(b) The speed of the mass has decreased to 3.28 m/s. How much work was done on the mass by the spring? Include the appropriate sign.

I've tried solving it by using change in Kinetic Energy = Work but I can't seem to get the right answer. Essentially I've been doing (1/2)*.081*(3.28^2-4.20^2)=W_earth + W_spring. I found W_earth to be 0.0714J did KE-W_earth to get W_spring, but that seems to be wrong.

Can someone who's familiar with doing these types of problems tell me what I'm missing?
 

TuxDave

Lifer
Oct 8, 2002
10,571
3
71
I wish I had a calculator to check your math but you have the correct approach. Not sure what you did wrong.
 

TecHNooB

Diamond Member
Sep 10, 2005
7,458
1
76
TuxDave, find a calc, get the answer, and get back to me T__T My life depends on it!
 

TuxDave

Lifer
Oct 8, 2002
10,571
3
71
Originally posted by: TecHNooB
I've tried -3.50252, 3.50105, and -3.49932.

I found a calculator and it's funny. I'm off by a factor of ten from you:

0.3501048 if you assume up as positive.
 

TecHNooB

Diamond Member
Sep 10, 2005
7,458
1
76
Zzz.. well as you can see i've tried that already T__T Still wrong =[

O wait, nm. Lemme try your answer =o
 

TecHNooB

Diamond Member
Sep 10, 2005
7,458
1
76
Wow. I had the answer the entire time but I just kept putting it in as -3.501 instead of -.3051 like tuxdave said... I guess I'm just havin one of those days...