Need some physics help

[Finns14]

I have a number of questions but I guess I will go one at a time here is the first.

A basketball player makes a jump shot. The 0.569-kg ball is released at a height of 2.27 m above the floor with a speed of 8.05 m/s. The ball goes through the net 3.20 m above the floor at a speed of 4.79 m/s. What is the work done on the ball by air resistance, a nonconservative force?

I guess I have to consider both the x and y direction but I am still rather lost. Any help would be greatly appreciated. Also for you jerks who are going to say do your own homework I am asking for explantions not answers. Thanks again.

 

[venk]

do your own homework.

 

[Finns14]

Originally posted by: venk
do your own homework.

LOL I knew it was coming either way

 

[SparkyJJO]

Also for you jerks who are going to say do your own homework I am asking for explantions not answers.

Originally posted by: venk
do your own homework.

:laugh:

 

[Heisenberg]

The easiest way to do it would be to use conservation of energy. Calculate how much energy (potential + kinetic) the ball had when it was released, and again when it went through the basket. The difference in energy is how much it lost due to air resistance, and thus the work done.

 

[Finns14]

I can give the answer if it helps anyone because the site that I do homework on generates new values for the question

 

[Finns14]

Originally posted by: Heisenberg
The easiest way to do it would be to use conservation of energy. Calculate how much energy (potential + kinetic) the ball had when it was released, and again when it went through the basket. The difference in energy is how much it lost due to air resistance, and thus the work done.

Ok this is making some sense to me let me try and see if I can get it

 

[BigJ]

You may want to make a force diagram to identify ALL of the forces acting on the ball.

 

[PurdueRy]

Originally posted by: Heisenberg
The easiest way to do it would be to use conservation of energy. Calculate how much energy (potential + kinetic) the ball had when it was released, and again when it went through the basket. The difference in energy is how much it lost due to air resistance, and thus the work done.

Agreed, this is the first method that I would have suggested

 

[Finns14]

Originally posted by: PurdueRy

Originally posted by: Heisenberg
The easiest way to do it would be to use conservation of energy. Calculate how much energy (potential + kinetic) the ball had when it was released, and again when it went through the basket. The difference in energy is how much it lost due to air resistance, and thus the work done.

Agreed, this is the first method that I would have suggested

I tried this method and I can't see to get it I'm using the formula 1/2mv^2+mgh calculate that for both half parts and subtract the difference and i can't seem to get it

 

[bonkers325]

Originally posted by: Finns14
I have a number of questions but I guess I will go one at a time here is the first.

A basketball player makes a jump shot. The 0.569-kg ball is released at a height of 2.27 m above the floor with a speed of 8.05 m/s. The ball goes through the net 3.20 m above the floor at a speed of 4.79 m/s. What is the work done on the ball by air resistance, a nonconservative force?

I guess I have to consider both the x and y direction but I am still rather lost. Any help would be greatly appreciated. Also for you jerks who are going to say do your own homework I am asking for explantions not answers. Thanks again.

conservation of energy.

work = change in kinetic + change in potential

you have all teh variables. just plug and chug.

 

[PurdueRy]

Originally posted by: Finns14
I have a number of questions but I guess I will go one at a time here is the first.

A basketball player makes a jump shot. The 0.569-kg ball is released at a height of 2.27 m above the floor with a speed of 8.05 m/s. The ball goes through the net 3.20 m above the floor at a speed of 4.79 m/s. What is the work done on the ball by air resistance, a nonconservative force?

I guess I have to consider both the x and y direction but I am still rather lost. Any help would be greatly appreciated. Also for you jerks who are going to say do your own homework I am asking for explantions not answers. Thanks again.

m*g*h1 + 1/2*m*(v1)^2 = m*g*h2 + 1/2*m*(v2)^2 + F

Plug and chug and solve for F

 

[Finns14]

Originally posted by: PurdueRy

Originally posted by: Finns14
I have a number of questions but I guess I will go one at a time here is the first.

A basketball player makes a jump shot. The 0.569-kg ball is released at a height of 2.27 m above the floor with a speed of 8.05 m/s. The ball goes through the net 3.20 m above the floor at a speed of 4.79 m/s. What is the work done on the ball by air resistance, a nonconservative force?

I guess I have to consider both the x and y direction but I am still rather lost. Any help would be greatly appreciated. Also for you jerks who are going to say do your own homework I am asking for explantions not answers. Thanks again.

m*g*h1 + 1/2*m*(v1)^2 = m*g*h2 + 1/2*m*(v2)^2 + F

Plug and chug and solve for F

Guess it must be and arithmatic error

 

[Finns14]

M and kg are both the correct units right?

 

[Fritzo]

OK, I predict you will spend most of the week staying home, watching TV, and on Saturday night, you will see a hot girl on the Internet, causing you to touch yourself.

EDIT: Oh, I'm sorry! I thought you needed some PSYCHIC help. Misread that. Sorry.

 

[Finns14]

Ok for the life of me I can't figure it out will I did exactly as follows

 

[PurdueRy]

In my quick calculation, I got 6.72 J