Need some math help, Algebra II

ViperMagic

Platinum Member
Jul 7, 2001
2,260
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Ok, I have to do these problems by Completing the Square, heres where I'm stuck...

X^2+4X-8=0
X^2+4X=8
X^2+4X+4=12
(X+2)^2=12
X+2=[Square root]12
Now what do I do? I have no idea. Help!
 

ViperMagic

Platinum Member
Jul 7, 2001
2,260
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Yeah, but dnot I have to do all that + crap? and then wouldnt I have to reduce all that? None of which I know how to do
 

fatalbert

Platinum Member
Aug 1, 2001
2,956
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ummm,


your math is wrong


(X+4)^2 = X^2+8X+16

not X^2+4X+4

so try factoring again and then it might make more sense
 

XZeroII

Lifer
Jun 30, 2001
12,572
0
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<<
X^2+4X-8=0
X^2+4X=-8
X^2+4X+4=12
(X+4)^2=12
X+2=[Square root]12
>>



X^2+4X-8=0
X^2+4X=8
X^2+4x+4=12
(x + 2)^2 = 12
Sqrt(x + 2)^2) = Sqrt(12)
X + 2 = Sqrt(12)
X = Sqrt(12) - 2

Took me a couple tries, but I got it. Remind me to never figure this out on a computer again. Pen and paper are the way to go.
 

GermyBoy

Banned
Jun 5, 2001
3,524
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0
Remember that you can turn root 12 into 2 * root 3. That way you can have 2 * (1 + root 3), which is good enough for any math teacher to jerk off to.