Need help with a Heat Load Study

cross6

Senior member
Jun 16, 2005
508
0
0
We've been having problems with our AC systems in our building.

I'm a network engineer - but I'm halfway done with an EE - I haven't taken any thermo.

So I need to figure roughly what is the heat load or dissipation of typical pc's, laser printers, etc etc.

Now I can measure the typical current consumption - and if I knew what % of that went to heat - then I would have a good idea...

How should I go about this?
 

DivideBYZero

Lifer
May 18, 2001
24,117
2
0
Conact the vendors of said components and ask if they have the BTU values for them. Often they will for calculating A/C for racking and so forth.
 

Heisenberg

Lifer
Dec 21, 2001
10,621
1
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Most stuff (if not all) should have its power usage on it somewhere. As for what percentage gets lost as heat, that depends on each device really. A good general ballpark figure is probably 50%.

Edit: FWIW, posting the same topic to more than one section (OT and HT) is generally frowned upon.
 

Sukhoi

Elite Member
Dec 5, 1999
15,342
104
106
Originally posted by: Heisenberg
Most stuff (if not all) should have its power usage on it somewhere. As for what percentage gets lost as heat, that depends on each device really. A good general ballpark figure is probably 50%.

Are you certain?
 

ElMonoDelMar

Golden Member
Apr 29, 2004
1,163
338
136
Originally posted by: Sukhoi
Originally posted by: Heisenberg
Most stuff (if not all) should have its power usage on it somewhere. As for what percentage gets lost as heat, that depends on each device really. A good general ballpark figure is probably 50%.

Are you certain?

Bad joke...
 

cross6

Senior member
Jun 16, 2005
508
0
0
Originally posted by: Heisenberg
Most stuff (if not all) should have its power usage on it somewhere. As for what percentage gets lost as heat, that depends on each device really. A good general ballpark figure is probably 50%.

Edit: FWIW, posting the same topic to more than one section (OT and HT) is generally frowned upon.

Oh sorry.



Isn't that power rating on devices the max?