Need help with a few physics questions - should be a breeze for you guys ...

BigKev

Platinum Member
Apr 29, 2000
2,315
0
0
1. Is momentum conserved in a two-deimensional collision? I know it isn't ... but I need to kno why, in scientific terms.

2. What are some reasons it isn't conserved?

Thanks guys.
 

DrPizza

Administrator Elite Member Goat Whisperer
Mar 5, 2001
49,601
167
111
www.slatebrookfarm.com
YES! Momentum is always conserved. I have to teach my next class in about 30 seconds, I'll check back at 3pm to see if that answer is good enough.
 

DT4K

Diamond Member
Jan 21, 2002
6,944
3
81
Momentum is always conserved. Outside forces may act upon the two objects though, so you have to consider that also.
 

DrPizza

Administrator Elite Member Goat Whisperer
Mar 5, 2001
49,601
167
111
www.slatebrookfarm.com
Okay... done teaching now...

To simplify calculations in a 2 dimensional system, find the x and y components of each object in the system (if an object is at rest, the x and y components of momentum = 0)

The find the sum of the x-components of momentum, and the sum of the y components of momentum. This is the net momentum in each direction and will remain the same (provided you don't add any forces).

Example that doesn't look like momentum is conserved. object moving to the right and an object moving to the left, but not perfectly lined up with each other. Initial net momentum in the y direction = 0. After they strike each other with a glancing blow, both of them travel off at some angle. A portion of the momentum of each is in the y direction. If you add the y components of each together, they will cancel out to give you a net momentum in the y direction of 0. (momentum is a vector; so since they're in opposite directions, define one direction as positive and one direction as negative)
 

roboninja

Senior member
Dec 7, 2000
268
0
0
Originally posted by: DrPizza
Okay... done teaching now...

To simplify calculations in a 2 dimensional system, find the x and y components of each object in the system (if an object is at rest, the x and y components of momentum = 0)

The find the sum of the x-components of momentum, and the sum of the y components of momentum. This is the net momentum in each direction and will remain the same (provided you don't add any forces).

Example that doesn't look like momentum is conserved. object moving to the right and an object moving to the left, but not perfectly lined up with each other. Initial net momentum in the y direction = 0. After they strike each other with a glancing blow, both of them travel off at some angle. A portion of the momentum of each is in the y direction. If you add the y components of each together, they will cancel out to give you a net momentum in the y direction of 0. (momentum is a vector; so since they're in opposite directions, define one direction as positive and one direction as negative)
What he said. Aren't I smrt?