need help on a calculus problem

[stickybytes]

I've been working on this problem all night and i can't seem to find the answer.

Find the limit of f(x) as x approaches 6

f(x)= y+6
----------------
y squared-36

Please also explain your steps.
Thanks.

 

[txrandom]

Ehh nvm,

 

[EyeMWing]

Uhhhhhhhhh. 12, because f(6) is 12.
Pay attention in class.

Oh, wait. WTF. Nevermind. Skip that problem, it's too much for me to think about tonight.

 

[IAteYourMother]

Originally posted by: stickybytes
I've been working on this problem all night and i can't seem to find the answer.

Find the limit of f(x) as x approaches 6

f(x)= y+6
----------------
y squared-36

Please also explain your steps.
Thanks.

are yous ure you copied it down right?
theer's no x in that equation

 

[TuxDave]

Originally posted by: stickybytes
I've been working on this problem all night and i can't seem to find the answer.

Find the limit of f(x) as x approaches 6

f(x)= y+6
----------------
y squared-36

Please also explain your steps.
Thanks.

I'm almost positive your problem was supposed to be.

lim (x-->6) of (x-6)/(x^2-36)

Either that or:

lim (x-->-6) of (x+6)/(x^2-36)

 

[ruffilb]

Originally posted by: stickybytes
I've been working on this problem all night and i can't seem to find the answer.

Find the limit of f(x) as x approaches 6

f(x)= y+6
----------------
y squared-36

Please also explain your steps.
Thanks.

uh, 6/-36 = -1/6

if it's ((x+6)/(x^2-36)) then

((x+6)/(x^2-36)) =
((x+6)/((x+6)(x-6)))

lim (x+6)/
x => 6 (x+6)(x-6)

=

lim 1/(x-6)
x => 6

= 1/0 indicating a vertical asymptote. If the top is (x-6), it comes out to be


((x-6)/(x^2-36)) =
((x-6)/((x+6)(x-6)))

lim (x-6)/
x => 6 (x+6)(x-6)

=

lim 1/(x+6)
x => 6

= 1/(6+6) = 1/12

 

[tfinch2]

I don't get it...

Where is the x variable in the function?

 

[Auryg]

Jus' type it in to yer graphing calc!

 

[IAteYourMother]

Originally posted by: ruffilb

Originally posted by: stickybytes
I've been working on this problem all night and i can't seem to find the answer.

Find the limit of f(x) as x approaches 6

f(x)= y+6
----------------
y squared-36

Please also explain your steps.
Thanks.

uh, 6/-36 = -1/6

wtf?

 

[ruffilb]

Originally posted by: Auryg
Jus' type it in to yer graphing calc!

Ti-89 ftw.

But 83-86's don't have a limit function.

 

[IAteYourMother]

Originally posted by: ruffilb

Originally posted by: Auryg
Jus' type it in to yer graphing calc!

Ti-89 ftw.

But 83-86's don't have a limit function.

so you just graph it and find y at x=6... not that hard

 

[ruffilb]

Originally posted by: IAteYourMother

Originally posted by: ruffilb

Originally posted by: stickybytes
I've been working on this problem all night and i can't seem to find the answer.

Find the limit of f(x) as x approaches 6

f(x)= y+6
----------------
y squared-36

Please also explain your steps.
Thanks.

uh, 6/-36 = -1/6

wtf?

A constant function and e^x are walking on Broadway. Then suddenly the constant function sees a differential operator approaching and runs away. So e^x follows him and asks why the hurry. "Well, you see, there's this differential operator coming this way, and when we meet, he'll differentiate me and nothing will be left of me...!" "Ah," says e^x, "he won't bother ME, I'm e to the x!" and he walks on. Of course he meets the differential operator after a short distance.
e^x: "Hi, I'm e^x"
diff.op.: "Hi, I'm d/dy"

XD

 

[ruffilb]

Originally posted by: IAteYourMother

Originally posted by: ruffilb

Originally posted by: Auryg
Jus' type it in to yer graphing calc!

Ti-89 ftw.

But 83-86's don't have a limit function.

so you just graph it and find y at x=6... not that hard

f(x)= y+6 doesn't graph.

And the OP probably want's to do it the legit way, although I must admit I use my graphing calculator like, 99% of the time 😉