I had a problem getting someone to help me the other day when I posted a math question, but I hope someone can do this one.
(y^(1/2))(dy/dx)+y^(3/2)=1
First I divide each term by y^(1/2) to get (dy/dx)+y=y^(-1/2)
next I say w=y^(3/2)
then dw/dx=3/2(y^(1/2))(dy/dx)
then I multiply both sides of (dy/dx)+y=y^(-1/2) by 3/2(y^(1/2)) to get
3/2[y^(1/2)](dy/dx)+3/2(y^(3/2))=3/2
So we plug dw/dx in and w to get
dw/dx+3/2w=3/2 since this is linear I say
u=e^(integral(3/2dx)) then you get u=e^(3x/2)
now I multiply each side of this dw/dx+3/2w=3/2 by e^(3x/2) to get
e^(3x/2)(dw/dx)+3/2w(e^(3x/2) )=3/2(e^(3x/2) )
I simplify this into d[(e^(3x/2))w]=3/2(e^(3x/2) )
take the integral of both sides to get [e^(3x/2)]w=e^(3x/2)+c
plug y^^(3/2) back into w and simply and the final anser is y^(3/2)=1+c[e^(-3x/2)]
(y^(1/2))(dy/dx)+y^(3/2)=1
First I divide each term by y^(1/2) to get (dy/dx)+y=y^(-1/2)
next I say w=y^(3/2)
then dw/dx=3/2(y^(1/2))(dy/dx)
then I multiply both sides of (dy/dx)+y=y^(-1/2) by 3/2(y^(1/2)) to get
3/2[y^(1/2)](dy/dx)+3/2(y^(3/2))=3/2
So we plug dw/dx in and w to get
dw/dx+3/2w=3/2 since this is linear I say
u=e^(integral(3/2dx)) then you get u=e^(3x/2)
now I multiply each side of this dw/dx+3/2w=3/2 by e^(3x/2) to get
e^(3x/2)(dw/dx)+3/2w(e^(3x/2) )=3/2(e^(3x/2) )
I simplify this into d[(e^(3x/2))w]=3/2(e^(3x/2) )
take the integral of both sides to get [e^(3x/2)]w=e^(3x/2)+c
plug y^^(3/2) back into w and simply and the final anser is y^(3/2)=1+c[e^(-3x/2)]