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More chemistry help needed please. Thanks in advance

M

MikeMike

Lifer
We did a lab the other day with NAHCO3(s) and then put HCl(aq) onto it, we then heated it and the byproduct was NaCl.

There are 2 questions i have.

1. Write a balanced equation for this reaction include all symbolisms. (s, aq, l, etc.)
would this just be....
NaHCO3(s)+HCl -----> NaCl(s)?

or what numbers would be added?

2. It says give the theoretical yield, in moles, for sodium chloride (based upon how much NaHCO3 you started with)

how would i do this?






here is all the data i have.

mass of....
evaporating dish +watch glass = 110.13g

evaporating dish+ watch glass + NaHCO3 = 112.63g

evaporating dish + watch glass + NaCl = 11.75

the three questions befor those were.

calulate...

amount of moles of sodium bicarbonate (NaHCO3)
i concluded this was .0298 moles of NaHCO3.

amount of moles of sodium chloride (NaCl)
i concluded this was .0277 moles of NaCl.

mole ratio of solid reactant to solid product(experimental)
i figured this would be .0298 moles of NaHCO3 / .0277 moles of NaCl



if you feel like it you could check my work here are the AMU's of all the elements within the problem

Na = 22.98977
H = 1.00794
C = 12.0111
O = 15.9994 (times 3 for NaHCO3)
Cl = 35.453


TIA and the better the explanation the more help is recieved thank you.

i dont know what the actual amount of product we should have gotten or how to get that and that i think is my problem with getting the theoretical yield of the product.



THANK YOU SO VERY MUCH

MIke
 
would it not be H2 gas now that i think of it since Hydrogen is more stable(or happy as our teacher puts it lol) as molecule rather then a single element? and so you would need NaHCO3(s) + HCl -----> NaCl + H2 + CO2 + O? how does the 3rd oxygen come out as a single element?


edit:
OK FINE edit ur post and put the H2 into it while i type mine out and make sure it is correct
 
Originally posted by: nourdmrolNMT1
would it not be H2 gas now that i think of it since Hydrogen is more stable(or happy as our teacher puts it lol) as molecule rather then a single element? and so you would need NaHCO3(s) + HCl -----> NaCl + H2 + CO2 + O? how does the 3rd oxygen come out as a single element?
Click to expand...
It is H2(g). Oxygen (O2) may be a product, but you need to look into that. Your book should have details.
 
Originally posted by: minendo
Originally posted by: nourdmrolNMT1
would it not be H2 gas now that i think of it since Hydrogen is more stable(or happy as our teacher puts it lol) as molecule rather then a single element? and so you would need NaHCO3(s) + HCl -----> NaCl + H2 + CO2 + O? how does the 3rd oxygen come out as a single element?
Click to expand...
It is H2(g). Oxygen (O2) may be a product, but you need to look into that. Your book should have details.
Click to expand...

so that would give me 2 Na , 3H, 2 C, 6 o, 1 Cl

which would produce, 2NaCl (that isnt possible is it?) H2, H?????, 2 CO2, O2??

or..

would i not need 2 HCl too because Na and Cl combine at a 1:1 ratio.

thus giving me 2 Na, 4 H, 2 C, 6 O, 2 Cl.

so the product would be

2 NaCl, 2 H2, 2 CO2, O2?

i think i am completely wrong help
 
I haven't done this experiment in ages so was NaCl the only product you were left with? As in, were all other products gas?
 
yes


plus the teacher put a match into one of his own little combinations of the stuff and the CO2 snuffed it out immediately, however i still think that O2 is there, just not enough to provide oxygen to the flame
 
The byproducts are NaCl and H2CO3, which immediately turns into H2O and CO2.

It's a straight reaction. No coeffecients needed.

Since it's a straight reaction you get as many moles out as you have moles of limiting reagent.
 
Originally posted by: Sukhoi
The byproducts are NaCl and H2CO3, which immediately turns into H2O and CO2.

It's a straight reaction. No coeffecients needed.
Click to expand...

it was heated over a flame so the H2O would evaporate, so i dont know how H2O would still be there.

and that is what i was thinking but the flame part causes evaporation sow, the H2O would evaporate too right? into H2 and O or would i need 2 NaH2CO3's to produce 2 H2 and O2?
 
Originally posted by: nourdmrolNMT1
Originally posted by: Sukhoi
The byproducts are NaCl and H2CO3, which immediately turns into H2O and CO2.

It's a straight reaction. No coeffecients needed.
Click to expand...

it was heated over a flame so the H2O would evaporate, so i dont know how H2O would still be there.

and that is what i was thinking but the flame part causes evaporation sow, the H2O would evaporate too right? into H2 and O or would i need 2 NaH2CO3's to produce 2 H2 and O2?
Click to expand...

You DO NOT get H2 OR O2 out. Period. 🙂 The H2O isn't even going to evaporate until it's over 100 ºC, and if it does you're just going to be left with solid NaCl and gaseous H2O and CO2.
 
Originally posted by: Sukhoi
Originally posted by: nourdmrolNMT1
Originally posted by: Sukhoi
The byproducts are NaCl and H2CO3, which immediately turns into H2O and CO2.

It's a straight reaction. No coeffecients needed.
Click to expand...

it was heated over a flame so the H2O would evaporate, so i dont know how H2O would still be there.

and that is what i was thinking but the flame part causes evaporation sow, the H2O would evaporate too right? into H2 and O or would i need 2 NaH2CO3's to produce 2 H2 and O2?
Click to expand...

You DO NOT get H2 OR O2 out. Period. 🙂 The H2O isn't even going to evaporate until it's over 100 ºC, and if it does you're just going to be left with solid NaCl and gaseous H2O and CO2.
Click to expand...

ok thanks Gaseous H2O 😕 oh well so the equation would look like this?

NaCHO3 + HCl -----> NaCl(s) + H2O (g) + CO2(g)

right? because the product did become solid afterwards per what the teacher has told us.

now can i get help on the second problem from anyone? that one is the one that has me really stumped and i thank you sukhoi and minendo
 
Yeah, pretty much.

NaHCO3 (s) + HCl (aq) -> NaCl (s) + H2CO3 (aq)

Then you get H2CO3 (aq) <-> H2O (l) + CO2 (g), although this equilibrium goes almost completely to the right so there is hardly any H2CO3 (aq) leftover.

Thus your final equation is:

NaHCO3 (s) + HCl (aq) -> NaCl (s) + H2O (l) + CO2 (g)

Then obviously your H2O is going to be (g) instead of (l) if you're boiling it.
 
Originally posted by: Sukhoi
Are you in Auburn, OH as in the one nearish to Geauga Lake?
Click to expand...

wow um yeah 5 minutes away dude

y?

and it is no longer geauga lake, it is Six Flags Worlds of Adventure


(route 43 is screwed for traffic now)

geauga lake road has been re routed around the park and parking lot now too
 
'Cause I be from Chardon. 🙂

Join Science Olympiad and do Qualitative Analysis. You'll learn that reaction like the back of your hand. 😀

I know it's Six Flags...Geauga Lake sounds better. 😛
 
Originally posted by: Sukhoi
'Cause I be from Chardon. 🙂

Join Science Olympiad and do Qualitative Analysis. You'll learn that reaction like the back of your hand. 😀

I know it's Six Flags...Geauga Lake sounds better. 😛
Click to expand...

yeah Geauga lake sounds better but Six Flags sounds better to the company cuz just the name means money

i am not that smart, plus i dont know if kenston even has a Science Olympiad team.

i have probably the lowest score right now in Honors Chem, just cuz i choke on tests but understand most of the material during class


now onto my second problem
 
reagent=????

we are only on ch. 8 and most of it is covered in ch 9 but reagent =? i know theoretical would equal (amount of NaCl moles / amount of reagent) x 100 to get the percentage, but i dont know what reagent is



sorry, i never happened to see your edit
 
Oh, reagent means reactant.

Sorry, no time to really work out the problem...big history paper due Thursday.

Since all your coefficients are 1, just see which of your reactants you have the least of and that should be the theoretical amount of each product you will get out.
 
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