More chem homework :(

[Mr Bob]

Here's a question that I need to know how to do by sometime tomorrow....

The light intensity that enters an eye?s pupil, is at least 1.5 x 10^-11 J/m^2 in order for an object to be visible.

The diameter of a spherical pupil is .006m.

Wavelength of the light is 5.5 x 10^-7 m.

Find the minimum required rate (in photons per sec) that the photons must enter the person?s eye, allowing the person to be able to see.

Possibly useful information:

h = 6.626x10^-34
v = frequency
c = 3.00x10^8 m/s

E = Energy
E = hv
E= (hc)/(wavelength)

Wavelength = (h)/((mass in kg)(velocity))

After reviewing information about how telescopes work, I came to this conclusion:

Since the diameter is .006m, and the wavelength is 5.5 x 10^-7 m, we take the diameter divided by the wavelength , and multiply that result by the light intensity.

(1.5 x 10^-11 J/m^2) * (.006m/5.5 x 10^-7m)

= 1.63636363636 x 10^-7 photons/sec

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Am I using the right formula for this?

I was able to get quite a bit of good advice last time I had a question, hopefully it will work out good for me again

 

[rezinn]

<-what a jerk huh