Hi,
I've posted this before, but not in a concise manner so no one knew what I was talking about...
Maybe this is more clear?
Anyway, I was wondering if anyone knew of a quick-ish way of solving the following problem:
Given n vectors (V(0), V(1), ..., V(n-1)) each with a maximum size (MS(0), MS(1), ..., MS(n-1)) and having elements from 0 to MS(n-1) - 1 (in ascending order), find the highest value HighVal from 0 to LCM(MS(0), MS(1), ..., MS(n-1))-1 that satisfies the following equation:
HighVal = A(0)*MS(0)+V(0)(B(0)) = A(1)*MS(1)+V(1)(B(1)) = ... = A(n-1)*MS(n-1)+V(n-1)(B(n-1))
Where A(x) is the multiplier of the array and B(x) is the element counter of an array (so, V(10)(12) would return the 12th element in the 10th array).
Does this make sense?
For instance, if I had 3 vectors:
V(0)=[0] (MS(0)=2)
V(1)=[1] (MS(1)=3)
V(2)=[2,3] (MS(2)=4)
The highest HighVal from 0 to LCM(2,3,4)-1 = 0 to 11 is 10.
The methods that I am currently using are pretty slow. BTW, there could be 150 to 300, each with 1000 to 50000 elements).
Thanks!
I've posted this before, but not in a concise manner so no one knew what I was talking about...
Maybe this is more clear?Anyway, I was wondering if anyone knew of a quick-ish way of solving the following problem:
Given n vectors (V(0), V(1), ..., V(n-1)) each with a maximum size (MS(0), MS(1), ..., MS(n-1)) and having elements from 0 to MS(n-1) - 1 (in ascending order), find the highest value HighVal from 0 to LCM(MS(0), MS(1), ..., MS(n-1))-1 that satisfies the following equation:
HighVal = A(0)*MS(0)+V(0)(B(0)) = A(1)*MS(1)+V(1)(B(1)) = ... = A(n-1)*MS(n-1)+V(n-1)(B(n-1))
Where A(x) is the multiplier of the array and B(x) is the element counter of an array (so, V(10)(12) would return the 12th element in the 10th array).
Does this make sense?
For instance, if I had 3 vectors:
V(0)=[0] (MS(0)=2)
V(1)=[1] (MS(1)=3)
V(2)=[2,3] (MS(2)=4)
The highest HighVal from 0 to LCM(2,3,4)-1 = 0 to 11 is 10.
The methods that I am currently using are pretty slow. BTW, there could be 150 to 300, each with 1000 to 50000 elements).
Thanks!
Facebook
Twitter