diagram
the question
"the ball has a weight of 75N (roughly 7.5Kg) and is fixed to a rod having a negligable mass. if it is released from rest when ? = 0°, determind the angle ? at which the compressive force in the rod becomes zero"
i have included a diagram up top.
my initial thinking is this....
if the compressive strength is to equal zero, then i my mind that means that (MV^2)/R (centripetal force) must be equal to the component of the 75N force in the same direction like this
but for this i need to find the velocity of the ball at that point dont i?
ive been trying to use
Ta + Va = Tb + Vb
where a is the initial state and b the state where the compressive force = 0
so Ta = 0 , Va = mgh = 75, Tb = 1/2 x 7.5 x v^2 and Vb= mgh = 75sin??
but i dunno where to go next as i dont know V and i dont know ?? (theta prime) ive also tried to put work done in the equation (SU1-2) but still stuck
any help is appreciated
the question
"the ball has a weight of 75N (roughly 7.5Kg) and is fixed to a rod having a negligable mass. if it is released from rest when ? = 0°, determind the angle ? at which the compressive force in the rod becomes zero"
i have included a diagram up top.
my initial thinking is this....
if the compressive strength is to equal zero, then i my mind that means that (MV^2)/R (centripetal force) must be equal to the component of the 75N force in the same direction like this
but for this i need to find the velocity of the ball at that point dont i?
ive been trying to use
Ta + Va = Tb + Vb
where a is the initial state and b the state where the compressive force = 0
so Ta = 0 , Va = mgh = 75, Tb = 1/2 x 7.5 x v^2 and Vb= mgh = 75sin??
but i dunno where to go next as i dont know V and i dont know ?? (theta prime) ive also tried to put work done in the equation (SU1-2) but still stuck
any help is appreciated
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