MCQ Question for all Networking Gurus!!!

[Juniper]

This is a question that has been plaguing me for quite some time. I am working on my revisions now, and I cannot get any answer that corresponds to the choices given... Any help and explanation given appreciated.


An application using UDP as the transport protocol, writes a buffer containing 4442 bytes of data. Assuming that the link level protocol is DIX Ethernet and no IP options are enabled, the number of overhead bytes generated from all layers as a result is:

A. 184
B. 82
C. 160
D. 176

 

[Juniper]

NVM I got it. Dumb assumption of mine. Its easy after all.

Ethernet frame max data = 1500 bytes
IP Header = 20 bytes
UDP Header = 8 bytes

Max Application data packet sie = 1500-20-8 = 1472 bytes

4442 bytes has to be broken into 3 packets of 1472 bytes and another packet of 26 bytes hence total numer of segments = 4

Overhead bytes generated from all layers = 4*(20+8+18) = 184 bytes