• We’re currently investigating an issue related to the forum theme and styling that is impacting page layout and visual formatting. The problem has been identified, and we are actively working on a resolution. There is no impact to user data or functionality, this is strictly a front-end display issue. We’ll post an update once the fix has been deployed. Thanks for your patience while we get this sorted.

Matrix math help

Status
Not open for further replies.
Kirby

Kirby

Lifer
So I got a general equation of a quadratic equation:

Ax^2 + By^2 + Cz^2 + Dxy + Exz + Fyz + Gx + Hy + Iz + J = 0

And I need to make an augmented matrix with 9 points to find the coefficients(A, B, C, etc).

I know how to do it for 2 dimensions, first column is 1, second is the x's, the second is x^2, and the last is y, then you just make it to a reduced echelon form, and you got all the coefficients.

But I have no clue how to form the augmented matrix in 3D.

Halp?
 
Is that what the question states exactly? Cause it can be translated/rotated to one of two standard forms. I vaguely remember this stuff from my muli-variable calc course a few years ago.
 
Question: The general equation of a quadratic surface is: Ax^2 + By^2 + Cz^2 + Dxy + Exz + Fyz + Gx + Hy + Iz + J = 0.

Consider the quadratic surface that contains the following points: (1,2,3) (2,1,0), etc. (there are 9 points).

(a) Implement the augmented matrix S of the system that determines the coefficients A through J of the equation of the surface.

(b) Key in an equation of the surface.

We haven't done 3d matrices, and i would hope he wouldn't have a Matlab lab that would include it.
 
Originally posted by: Cawchy87
Sorry bud, it's been too long for me. Good luck with it. What are you taking in school?
Click to expand...

I'm a CS major, and this is for my Applied Matrix Theory math class. This is the last question for the lab, and I've been searching like hell for a hint.
 
Ah, I took this stuff in a different course not concentrating on matrices and only using them when necessary (jacobian etc.). Wish I could help ya out. Look up the guru's who help on other math threads, they might be able to help you out.
 
I think I got it. If I put it into the equation into reduced echelon form, I get A through I in terms of J. Then put it back into the equation, substituting A-I with J, then divide out J. So now I've got coefficients with all of the x,y,z's.
 
Status
Not open for further replies.

TRENDING THREADS

Back
Top