Math problems..................

BustaBust

Golden Member
Dec 21, 2001
1,425
2
81
How do you do this:

20. For the following set of scores, find the value of each expression:

X
------
5
-2
0
3
a. SX
b. SX2
c. S(X + 3)


24. For the following set of scores, find the value of each expression:

X
-------
9
1
1
1
a. SX2
b. (SX)2
c. S(X ? 3)
d. S(X ? 3)2

It is fairly easy, but I've been away from Math so long that I am not confident in my answer.
 

dullard

Elite Member
May 21, 2001
25,561
4,060
126
SX = x1+x2+x3+...

Thus SX = 5 + -2 + 0 + 3 = 6

The rest are the same technique.
 

BustaBust

Golden Member
Dec 21, 2001
1,425
2
81
I got these: (Correct me if I am wrong)

20
A. 6
B. 36
C. 9

24
A. 144
B. 144
C. 9
D. 81

Remember 20b, 24a, 24b, and 24d are supposed to be squared not "2"
 

Gunslinger08

Lifer
Nov 18, 2001
13,234
2
81
Originally posted by: BustaBust
I got these: (Correct me if I am wrong)

20
A. 6
B. 36
C. 9

24
A. 144
B. 144
C. 9
D. 81

Remember 20b, 24a, 24b, and 24d are supposed to be squared not "2"

Incorrect.
Check your answers.
Mine are correct.
 

dullard

Elite Member
May 21, 2001
25,561
4,060
126
Originally posted by: BustaBust
I got these: (Correct me if I am wrong)
The issue is the order of operations. The parenthesis is most important. Do whatever is inside them first, then do the rest. Squaring is more important than adding, so square before you add. Thus:

SX = x1 + x2 + x3 + x4

SX^2 = x1^2 + x2^2 + x3^2 + x4^2

S(X + 3) = (x1+3) + (x2+3) + (x3+3) + (x4+3)

(SX)^2 = (x1 + x2 + x3 + x4) ^ 2

S(X - 3) = (x1-3) + (x2-3) + (x3-3) + (x4-3)

S(X ? 3)^2 = (x1-3)^2 + (x2-3)^2 + (x3-3)^2 + (x4-3)^2

I did the math quickly in my head and joshsquall appeard to get them correct.

Sorry I put the sum in, but when I edited the post, the sums left, pretend the 'S' is the summation sign.