Here's a problem I found on abcnews.com along with the solution.
I follow the solution until one part, where I get lost.
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A Tricky Problem
A mathematics question is not inappropriate in a discussion of the SAT so let me include here a tricky one. In the correctly solved additions below, each of the five letters represents a different digit, EA being a two-digit number. What is the value of B + D if
A C
+B +D
-- --
C EA
Solution: Combining the two additions yields A+B+C+D=C+EA. If we cancel the C's from both sides of this equation, we obtain A+B+D=EA, and thus B+D=EA-A. The two-digit number EA equals 10xE+A, and so EA-A equals (10xE+A)-A, or simply 10xE. Since the digit E must be 1, (B+D)=10x1 or just plain 10. There are other approaches as well.
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I don't understand how the following conclusion is reached "Since the digit E must be 1..." E can also be 2-9. It seems like a huge jump to me.
I emailed the author to have him explain by saying "how ya figure?"
Hopefully, he'll respond soon... cause I've been mulling this damn thing for 3 hours... it's prevented my from sleeping and the damn sun's up now.
