Oh sure, this morning you posted that you were leaving. Now, you come crawling back because you discover you need us.
Have you tried looking at the answer to deduce what might work for solving it? (wolframalpha is able to compute this)
(2x^(3)-y)dx+(2x^(2)y+x)dy=0
(2x^(3)-y)dx=-(2x^(2)y+x)dy
There is the first steps...now do the rest.
So you're what? 1 week into the school year and you're already stumped?
Good luck!
go to office hours
no help for quitters.

gibson had the first part, now divide by d.
Alas ...and another young mind is lost to "see office hours". 😉
The equation listed above is unsolveable. I was hoping that someone would solve it which would complete my life's work. Then I could steal their idea and get a Fields Medal or a Nobel Prize.![]()
You're paying for your professor to be in those office hours. Your professor is there to help with cases like yours. You might as well go.
not even close, unless you're a non-resident then it's a remote possibility. Even then, don't try to tell that to your professor, he/she will just laugh at them and give you that "are you stupid?" look.
professors are there to do research and get grants for the school, it's the TAs' job to deal with not too bright students and engineer wanna be's.
At least that what it felt like when I was in college.
You're paying for your professor to be in those office hours. Your professor is there to help with cases like yours. You might as well go.
Open your diffeq book and read?
Or this 😛
Please note you will fail the class if you have to use the link. 🙁
Bastard! I tossed it in wolframalpha & it solved it. But by hand, I monkeyed around for about 10 minutes before I decided I must be too rusty at diff eqs.
not even close, unless you're a non-resident then it's a remote possibility. Even then, don't try to tell that to your professor, he/she will just laugh at them and give you that "are you stupid?" look.
professors are there to do research and get grants for the school, it's the TAs' job to deal with not too bright students and engineer wanna be's.
At least that what it felt like when I was in college.