*Originally posted by: ***thegreatjeff**
*Originally posted by: ***Alphathree33**

I don't know what ya'll are smoking but this is fairly easy. It was designed to work out nicely.

Look,

1 / (1 + root2 + root3)

= 1 / [(1 + root2) + root3]

= [1 + root2 - root3] / [(1 + root2)^2 - 3] (multiplied by the conjugate of the bottom, taken as two terms not three)

= [1 + root2 - root3] / [1 + 2root2 + 2 - 3]

= [1 + root2 - root3] / [2root2]

= [root2 + 2 - root6] / 4

Done.

Sorry, that doesn't work...the original problem, when divided, was roughly .24118, and that answer equals roughly 1.4659. The problem comes in after you mulptiplied by the conjugate, because on line four of your answer, it should look like this once you square the (1+root2):

= [1 + root2 - root3] / [1 + (sq. root of 2) + (sq. root of 2) + (sq. root of 2) + (sq. root of 2)]

or...

= [1 + (sq. root of 2) + (sq. root of 3)] / [1 + (sq. root of 2)(4)]

Correct me if I'm wrong, I think I'm not getting something in your answer...