Originally posted by: Marty
Can anyone figure out this integral:
integral of (x^2)exp(x)exp(-x^2)dx
Good luck...
Originally posted by: Marty
What is incoherent about that?
integral of x^2 * exp(x) * exp(-x^2) * dx
btw, exp(x) = e^x
Originally posted by: Zakath15
So it's x^2 * e^{-x^3}?
Originally posted by: agnitrate
Originally posted by: Zakath15
So it's x^2 * e^{-x^3}?
I think that's what it should be.
Here's a hint : Think power rule.
-silver
Originally posted by: Zakath15
So it's x^2 * e^{-x^3}?
Originally posted by: Heisenberg
I did it on wolfram's integrator site b/c I don't have my TI-89 handy. The answer's pretty complicated:
E^(x-x^2) *(1/4 - x/2) + (3/8)*E^1/4 * sqrt(pi) * Erf [1/2 (-1 + 2x)]
Originally posted by: AgentEL
Originally posted by: agnitrate
Originally posted by: Zakath15
So it's x^2 * e^{-x^3}?
I think that's what it should be.
Here's a hint : Think power rule.
-silver
isn't it x^2 * e^{x-x^2}
Originally posted by: eLiu
uh...it's not e^(-x^3), it's e^(x-x^2), although the former is MUCH more doable than the latter. Maple yields this for the latter:
-1/2*x*exp(x-x^2)-1/4*exp(x-x^2)+3/8*Pi^(1/2)*exp(1/4)*erf(x-1/2)
erf is some sort of an error function, but I forgot exactly how it works.