Lyapunov Stability

hypn0tik

Diamond Member
Jul 5, 2005
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Anyone familiar with this concept?

One question I was assigned was:

Consider x' = Ax
Show that the origin is stable if:

A =
0 ..1
-1 0

(A = 2x2 matrix).

I found the eigen values to be:

det (A-bI)= 0
-> b^2 + 1 = 0 => b = i or b = -i

However, for it to be stable, the real part of the eigen value must be strictly less than 0.

Anyone have any ideas? Am I missing anything?
 

Heisenberg

Lifer
Dec 21, 2001
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It looks like you found the correct eigenvalues. As far as I can tell they're both purely imaginary, which means the real part would be zero.
 

aux

Senior member
Mar 16, 2002
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IIRC, the Lyapunov stability condition is: the eigenvalues should have non-positive real parts and the eigenvalues with zero real parts should be different.

edit: typo fixed
 

hypn0tik

Diamond Member
Jul 5, 2005
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Originally posted by: Heisenberg
It looks like you found the correct eigenvalues. As far as I can tell they're both purely imaginary, which means the real part would be zero.

Yes, I understand that, but it says that I need to prove that the system is stable around the origin. However, since the real part of the eigen values are NOT less than zero, how do I go about it?
 

Heisenberg

Lifer
Dec 21, 2001
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Originally posted by: hypn0tik
Originally posted by: Heisenberg
It looks like you found the correct eigenvalues. As far as I can tell they're both purely imaginary, which means the real part would be zero.

Yes, I understand that, but it says that I need to prove that the system is stable around the origin. However, since the real part of the eigen values are NOT less than zero, how do I go about it?
Eh, I dunno. I've never heard of Lyapunov Stability, but I can find eigenvalues in my sleep. ;) However, if what aux posted is right, then you should be okay.
 

PurdueRy

Lifer
Nov 12, 2004
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" continuous-time linear time-invariant system is Lyapunov stable (internally stable) if and only if all the eigenvalues of A have real parts less than or equal to 0, and those with real parts equal to 0 are nonrepeated."

Doesn't that hold in your answer...?
 

hypn0tik

Diamond Member
Jul 5, 2005
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Originally posted by: aux
IIRC, the Lyapunov stability condition is: the eigenvalues should have non-positive real parts and the eigenvalues with zero real parts should be different.

edit: typo fixed

See, the problem is the notes I am using do not discuss the case where the real part is 0.
 

PurdueRy

Lifer
Nov 12, 2004
13,837
4
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Originally posted by: hypn0tik
Originally posted by: aux
IIRC, the Lyapunov stability condition is: the eigenvalues should have non-positive real parts and the eigenvalues with zero real parts should be different.

edit: typo fixed

See, the problem is the notes I am using do not discuss the case where the real part is 0.

if all the eigenvalues of A have real parts less than or equal to 0, and those with real parts equal to 0 are nonrepeated
 

hypn0tik

Diamond Member
Jul 5, 2005
5,866
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Originally posted by: PurdueRy
" continuous-time linear time-invariant system is Lyapunov stable (internally stable) if and only if all the eigenvalues of A have real parts less than or equal to 0, and those with real parts equal to 0 are nonrepeated."

Doesn't that hold in your answer...?

Yes, it holds. Where did you find that?

Thanks.
 

PurdueRy

Lifer
Nov 12, 2004
13,837
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Originally posted by: hypn0tik
Originally posted by: PurdueRy
" continuous-time linear time-invariant system is Lyapunov stable (internally stable) if and only if all the eigenvalues of A have real parts less than or equal to 0, and those with real parts equal to 0 are nonrepeated."

Doesn't that hold in your answer...?

Yes, it holds. Where did you find that?

Thanks.

http://academic.csuohio.edu/simond/linearsystems/stability/lyapunov/

::shrug:: first google link
 

aux

Senior member
Mar 16, 2002
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Originally posted by: hypn0tik
Originally posted by: aux
IIRC, the Lyapunov stability condition is: the eigenvalues should have non-positive real parts and the eigenvalues with zero real parts should be different.

edit: typo fixed

See, the problem is the notes I am using do not discuss the case where the real part is 0.


Looks like your lecture notes are missing the zero real parts case, try google for more info.

edit: PurdueRy found a link for you :)
 

hypn0tik

Diamond Member
Jul 5, 2005
5,866
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Originally posted by: aux
Originally posted by: hypn0tik
Originally posted by: aux
IIRC, the Lyapunov stability condition is: the eigenvalues should have non-positive real parts and the eigenvalues with zero real parts should be different.

edit: typo fixed

See, the problem is the notes I am using do not discuss the case where the real part is 0.


Looks like your lecture notes are missing the zero real parts case, try google for more info.

Yeah, that seems to be the problem.

I tried Wiki and didn't find anything useful there either.

Thanks everyone. I appreciate the help.