Little Math problem here...care to help?

Nutdotnet

Diamond Member
Dec 5, 2000
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I'm sure this is easy for somebody out there, I am just a math idiot...

I have uploaded roughly 7.3gigs in the last 23days. My upload speed is 256kbits per second.

First how much per day would that be? And How much would it be possible to upload at my max speed if I was constantly doing it 24hours a day for those 23days?

Thanks!
 

RaynorWolfcastle

Diamond Member
Feb 8, 2001
8,968
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Oh come on... just click start > programs > accessories > calculator, I'm pretty sure you can handle this on your own ;)

-Ice
 

Nutdotnet

Diamond Member
Dec 5, 2000
7,721
3
81


<< Oh come on... just click start > programs > accessories > calculator, I'm pretty sure you can handle this on your own ;)

-Ice
>>



Uh....if I could I wouldn't have posted the question......
rolleye.gif

I know it is a simple question but I don't want to screw it up, I want someone who is confident in their math skills to do it because I am having certain issues with my cable provider and need to use the info in my defense....

I believe it is roughly 318 mb per day....that is all I can figure out.
 

RaynorWolfcastle

Diamond Member
Feb 8, 2001
8,968
16
81
OK, here's the general idea
7.3 GB * 1024 MB/GB / 23 days ~= 325 MB per day

256 kbps / (8 bits/Byte) / (1024 KB/MB) / (1024 MB/GB) * (3600 seconds/hour) * (24 hours/day) * 23 days ~= 61 GB

This does not take overhead into account which would guess would add a few percents to both figures.

That wasn't that painful now was it :)

-Ice
*edit* that's roughly 2.6 GB a day
 

b0mbrman

Lifer
Jun 1, 2001
29,470
1
81


<< I'm sure this is easy for somebody out there, I am just a math idiot...
I have uploaded roughly 7.3gigs in the last 23days. My upload speed is 256kbits per second.
First how much per day would that be? And How much would it be possible to upload at my max speed if I was constantly doing it 24hours a day for those 23days?
Thanks!
>>


The gist is multiplying what you have by one a bunch of times... (I.E. 24 hours = 1 day so 24 hours/1 day = 1)

You upload at 256 kilobits / 1 second (that's a 1)
There are 60 seconds / 1 minute (another 1)
60 minutes / 1 hour
24 hours / 1 day
23 days / 1 Cycle (I made the word cycle up...it's just a definition for how long you want to count)
And we all know that there is 1 gb / 1024 mb
1 mb / 1024 kb
1 kb / 8 kilobits

Then, you just multiply everything together (Notice how all the units cancel out?) This is okay because everything equals 1...and we all know that anything times 1 is still the same ;)

(256 kilobytes / 1 second)(60 seconds / 1 minute)(60 minutes / 1 hour)(24 hours / 1 day)(23 days / 1 Cycle)(1 gb / 1024 mb)(1 mb / 1024 kb)(1 kb / 8 kilobits)

we get:

60.64 (kb)(sec)(min)(hr)(day)(gb)(mb)(kb) / (sec)(min)(hr)(day)(Cycle)(mb)(kb)(kilobits)

Cancelling out common factors, that turns into:

60.64 gb/Cycle
 

clarkmo

Platinum Member
Oct 27, 2000
2,615
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81
My downloads 1.4mbps max out at 150-160 kilobytes per sec. My uploads 256k max out at about 22 kilobytes per sec. So, realistically, you could expect 38.8 gigs uploaded over 23 days. or 1.68744 per day. :)