Linux BASH: Finding files and then getting sum of those files?

[Namuna]

Goal:
Find log files, in a specific directory, generated in a 24hr period (could be THOUSANDS), then sum up the size of the result so as to know how much space is being used in a given 24hr period.

Commands tried so far:
- 'find ./ -type f -mtime -1 -exec du -sch'
The 'du' command is tallying up EACH file, instead of the whole result
- 'find ./ -type f -mtime -1 | xargs du -sch'
This gives a false result because xargs breaks the results (from find) into chunks of lines so as to not exceed the buffer limit, which throws off the du command

Suggestions/Help is much appreciated!

Thanks.

 

[Cheetah8799]

I haven't done enough bash scripting recently to be able to come up with the syntax for you, but I have made good use of this site in the past when I have BASH questions.

http://www.tldp.org/LDP/abs/html/

 

[bersl2]

Try this:

find . [whatever conditions] -exec du -s '{}' \; > sumfile
cut -f1 sumfile > sumfile2
(( i=1 )); (( count=`wc -l sumfile2 | cut -d' ' -f1` - 1 )); while (( i <= count )); do
echo + >> sumfile2
(( ++i ))
done
echo p >> sumfile2
dc -f sumfile2

It's probably easier to write a small C program though.

 

[Namuna]

thanks for the responses guys...I actually found a way to get the job done using something like this:

TOTAL_SIZE=0
for i in `find . -type f -mtime -1 | xargs du -sc | grep total | awk '{print $1}'
do
TOTAL_SIZE=`expr $TOTAL_SIZE + $i`
done
echo $TOTAL_SIZE