Lets help ViperMagic do some Geometry!

GoodToGo

Diamond Member
Jul 16, 2000
3,516
1
0
Is this a parallelogram? Because if it is, then the solution is real simple.
 

minendo

Elite Member
Aug 31, 2001
35,558
16
81
Originally posted by: GoodToGo
Is this a parallelogram? Because if it is, then the solution is real simple.
You must solve the problem using only the given and theorems/postulates.

 

RbSX

Diamond Member
Jan 18, 2002
8,351
1
76
Can't be a parallelogram or the oppisite sides would be marked as equal. But yeah I think some parts are missing.
 

ViperMagic

Platinum Member
Jul 7, 2001
2,260
0
0
that is exactly whats in the book. Though this is chapter on triangle inequalitys... (two sides of a triabgle must be greater than the thrid) if that helps
 

Yomicron

Golden Member
Mar 5, 2002
1,735
1
81
k, I haven't done geometry in a long time, but:

if MN == 0 then ON = OM = PO

so, PO + MN = ON , therefore PO + MN !> ON

so it is disproved by example
 

GoodToGo

Diamond Member
Jul 16, 2000
3,516
1
0
You cant prove anything without being given some characteristics of this shape. If it is a parrallelogram, then I can tell the solution pretty easily:

PO = MN = OM
OM + MN > ON (sums of two sides of a trianlge is greater than the third side)
But since PO = OM,
PO + MN > ON
 

Darien

Platinum Member
Feb 27, 2002
2,817
1
0
Well, you're given a Triangle MNO.

The length of MO is set and is Equal to PO.

|MO| = |PO|

You know that the sum of length of the smaller sides of a triangle is greater than the length of the largest side, and that the sum of the length of any two sides is greater than the third side.

Since you don't know the length of MN and ON, you have 3 situations

|MN| = |ON|, |MN| > |ON|, |MN| < |ON|



if |MN| = |ON|, then |x| + |MN| > |ON|

if |MN| > |ON|, then no matter what |x| you add, |x| + |MN| > |ON|

if |MN| < |ON|, you know that |MO| + |MN| > |NO|. Substitute |MO| for |PO|, then |PO| + |MN| > |NO|



I'll leave it up to you to construct a more formal proof.
 

Bobomatic

Senior member
Dec 31, 2001
514
0
0
just skip it and move on to the next problem, and if it needs to be done for class, copy the asian kids homework before class.
 

Darien

Platinum Member
Feb 27, 2002
2,817
1
0
Originally posted by: Bobomatic
just skip it and move on to the next problem, and if it needs to be done for class, copy the asian kids homework before class.

Words of wisdom :)