Integration question

PowerMacG5

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Apr 14, 2002
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My teacher gave us this problem as a challenge, no credit (it is not homework). I am trying to figure out how to do it, but I can't find where to start from. I have tried the majority of my trig identities and can't get it. here is the problem:

Find all of the anti-derivatives of sin^2(x). Any help would be appreciated.
 

agnitrate

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Jul 2, 2001
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you mean (sin(x))^2 ?

I think the trig identity is like 1/2 - 1/2 cos(2x) ? It's something like that.

-silver
 

agnitrate

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Jul 2, 2001
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Originally posted by: agnitrate
you mean (sin(x))^2 ?

I think the trig identity is like 1/2 - 1/2 cos(2x) ? It's something like that.

-silver

Yeah, I'm right. That's the trig identity. From there, it's just simple integration. Go nuts.
 

PowerMacG5

Diamond Member
Apr 14, 2002
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Originally posted by: agnitrate
you mean (sin(x))^2 ?

I think the trig identity is like 1/2 - 1/2 cos(2x) ? It's something like that.

-silver

Yeah, some people don't understand that sin^2(x) = (sin(x))^2, so I thought I would write it the "conventional" way.

Originally posted by: compudog
Do your own homework. I didn't have teh interweb to help me with mine.... ;)

I know part of this answer is sarcastic, just not which part. As I said, this is not homework, it's for us to find out about, and do for "fun."
 

PowerMacG5

Diamond Member
Apr 14, 2002
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Originally posted by: agnitrate
Originally posted by: agnitrate
you mean (sin(x))^2 ?

I think the trig identity is like 1/2 - 1/2 cos(2x) ? It's something like that.

-silver

Yeah, I'm right. That's the trig identity. From there, it's just simple integration. Go nuts.

Thanks, I will try.

EDIT: Also, how did you derive that trig identity? I'm just curious to how it was found, if you know. If it was just given to you, without a proof, I guess I could try to dig it up somewhere.