Integral calculus anyone?

[StealthElephant]

Hopefully someone here enjoys this stuff. I've been trying to get it to work out for like 30 minutes now.

Reiman Sums

2x^2 + 10 on the interval [0,12]

Using the fundamental theory of calculus gives 1272 as the answer, that is the correct answer.

Teacher wants to see it done with Reiman Sum, I can't get the answer doing it that way.

I followed the steps, my only doubt is where you turn k^2 into n(n+1)(2n+1) divided by 6.


Your then supposed to take the limit of and get a number as n approaches infinity.

So right now I have:

192 * (2n^2+3n+1)/(n^2) + 120

In order to get 1272 I need to get 192 * 6 + 120 = 1272. How do I know that the middle section gives 6 as n approaches infinity?

 

[agnitrate]

Correct me if I'm wrong, but aren't Riemann sums an approximation?

That's what I always thought they were. Why don't you post the formula you're using.

-silver

 

[Dudd]

Yeah, as long as you are relatively close with Rieman sums, you are golden. All it is setting up squares using the function as a height and then adding up all the sums, so it won't be perfect.

 

[StealthElephant]

Here is the formula

She wants the exact area of the definate integral.

Replace the "i" in the forumla with "k"