I'm having quite a bit of a difficult time solving this one problem (calc I level stuff)

[beer]

f(x) = (3-2x-x^2)/(x^2-1)

So I get

f'(x) = [ (x^2-1)(3-2x-x^2)' - (3-2x-x^2)(x^2-1)' ] / (x^2-1)^2

thus
f'(x) = [ (x^2-1)(-2-2x) - (3-2x-x^2)(2x) ] / (x^2-1)^2

The answer is 2/(x+1)^2

Help me get to it please.

 

[b0mbrman]

Ack...well, just multiply it all out...

 

[beer]

I realize that. Something I am doing though is not right and I need to see where I am making the mistake in multiplying it all out.

 

[erub]

why didn't you factor it?

Of course I'm just two weeks into Calculus AB so take it with a grain of salt.

oops i see a mistake on my part
heeh

 

[beer]

Quotiet Rule buddy boy