If one billion people on one side of the planet can be orchestrated to jump up at the same time

SSSnail

Lifer
Nov 29, 2006
17,458
83
86
Assuming they're packed together in a space that can accommodate 1 billion people. Yes, they ate.

Edit: Here are some more variables so some physics dudes to plug them in an equation somewhere.

Assuming average weight is 130 lbs
Assuming each human footprint is 2^ft
Assuming the average height of the jump is 1.2 feet


GOGOGO!
 

nerp

Diamond Member
Dec 31, 2005
9,865
105
106
nothing.

ever hear of massive earthquakes? that's a lot more than just some meat moving up and down maybe a foot. You don't feel huge earthquakes on the other side of the world.
 

SSSnail

Lifer
Nov 29, 2006
17,458
83
86
Originally posted by: EvilYoda
What kind of shoes are they wearing?

I'm thinking knocked off Nikes.

But assuming the average weight is 130 lbs per human, that's... a lot of weight.
 
Oct 4, 2004
10,515
6
81
Resonance cascade. Facehuggers would spawn out your ass and then suck your face into their assholes. It'd be weird, brah.
 

Leros

Lifer
Jul 11, 2004
21,867
7
81
The earth would move by an unmeasurable amount. But the mass of the people is way way way way way way way way way way less than the mass of the Earth, so it would very small.
 

gsethi

Diamond Member
Feb 28, 2002
3,457
5
81
F = ma

m = 130/2.2 = 59.09 Kg x 1,000,000,000 = 59,090,000,000 Kg
a = g = 9.8m/s2
so, F = 9.8 x m = 579,082,000,000 N

Someone double check my work...lol...i am sure someone will find a mistake since this is ATOT....lol

Now the real question is, say we have a teeter totter and OP is on one side of teeter totter and above mentioned 1 billion people jump simultaneously on the other side of the teeter totter...how high will OP fly ? :D Would love to see that in real life..LOL
 

Fenixgoon

Lifer
Jun 30, 2003
33,418
13,039
136
Originally posted by: gsethi
F = ma

m = 130/2.2 = 59.09 Kg x 1,000,000,000 = 59,090,000,000 Kg
a = g = 9.8m/s2
so, F = 9.8 x m = 579,082,000,000 N

Someone double check my work...lol...i am sure someone will find a mistake since this is ATOT....lol

F = dp/dt :p

the actual force experienced will depend on the duration of the impact and the change in momentum :)

so you're better off assuming something like:

your average person can jump 0.3m
let's stick with 60kg for average mass
let's assume everyone lands with stiff knees, duration of impact is 1ms

F= dp/dt ~~ m (delta v)/(delta t)

for a fall of 0.3m (and negligible drag forces), velocity on impact is:
0.3 = (0.5)*(9.8)*t^2 ---> t = 0.2474s
:: v = 0.2474*9.8 = 2.42 m/s

assume 0 velocity after impact
F = (10^9)*60*(0 - 2.42) / (0.001)
F = -1.452 * 10^14 N.
 

gsethi

Diamond Member
Feb 28, 2002
3,457
5
81
Originally posted by: Fenixgoon
Originally posted by: gsethi
F = ma

m = 130/2.2 = 59.09 Kg x 1,000,000,000 = 59,090,000,000 Kg
a = g = 9.8m/s2
so, F = 9.8 x m = 579,082,000,000 N

Someone double check my work...lol...i am sure someone will find a mistake since this is ATOT....lol

F = dp/dt :p

the actual force experienced will depend on the duration of the impact and the change in momentum :)

Bastage..lol...solve the edit for me now ;) here it is:
Now the real question is, say we have a teeter totter and OP is on one side of teeter totter and above mentioned 1 billion people jump simultaneously on the other side of the teeter totter...how high will OP fly ? :D Would love to see that in real life..LOL
 

Leros

Lifer
Jul 11, 2004
21,867
7
81
Originally posted by: gsethi
F = ma

m = 130/2.2 = 59.09 Kg x 1,000,000,000 = 59,090,000,000 Kg
a = g = 9.8m/s2
so, F = 9.8 x m = 579,082,000,000 N

Someone double check my work...lol...i am sure someone will find a mistake since this is ATOT....lol

Now the real question is, say we have a teeter totter and OP is on one side of teeter totter and above mentioned 1 billion people jump simultaneously on the other side of the teeter totter...how high will OP fly ? :D Would love to see that in real life..LOL

Finish the math and figure out how far the Earth would move. I did it back in high school physics, but I forget what the result was.
 

Flipped Gazelle

Diamond Member
Sep 5, 2004
6,666
3
81
Originally posted by: SSSnail
Assuming they're packed together in a space that can accommodate 1 billion people. Yes, they ate.

Edit: Here are some more variables so some physics dudes to plug them in an equation somewhere.

Assuming average weight is 130 lbs
Assuming each human footprint is 2^ft
Assuming the average height of the jump is 1.2 feet


GOGOGO!

Must be the Asian side of the world.
 

IEC

Elite Member
Super Moderator
Jun 10, 2004
14,604
6,091
136
People would get bored leading up to it and make "babby"
 

Skyclad1uhm1

Lifer
Aug 10, 2001
11,383
87
91
You also have to take into account that it is not a flat surface, and that those people don't all jump in exactly the same spot.
 

SSSnail

Lifer
Nov 29, 2006
17,458
83
86
Originally posted by: Lonyo
2^ft for the average human footprint? Are you crazy?
We're not freaking sardines, gotta give them room to jump you know. I know they don't all jump from one spot, hence the a constant was given so it can be calculated. How much freaking space do you need? 5^ft? I did say average of 130 lbs per human, not YOUR average of 250 lbs.
 

Mo0o

Lifer
Jul 31, 2001
24,227
3
76
Not that much. Total energy would be 2.11e11 J, less than 1 kiloton of TNT.
 

AstroManLuca

Lifer
Jun 24, 2004
15,628
5
81
If everyone in the U.S. jumped, it would have a greater effect.





















Because everyone in the U.S. is fat. Get it?