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I need homework help...

T

Tab

Lifer
I did get through the first couple problems I swear!

Alright, I've got a secant line with two points. (-3,3) and (7,-3). This was no problem, just got to find the slope of the line from (-3,3) and (7,-3). With my average rate of change formula I use that and get - 1 1/2. No problem.

Now, the second part is where I "think" i am suppose to use the Difference Quotient - f(t+h)-f(t)/h -

What I've got to figure out is, find all the numbers "t" so that the average rate of p(x) between x=-4 and x=t is zero...

The harder part is where is ask me to find number X where the average rate of change of p(x) between x=-3 and x=b is small as possible.

If anyone wants to help me out this late at night, thanks 🙂
 
Hmm, that looks/sounds like something I should be able to do (or rather I feel it is since it seems like something I've done before), but I can't remember what to do at all.

Here's a bump for you, and hopefully someone can help ya out.
 
I guess my explanation was bad? I'll post it verbatium.

Figure 4 (A secant line on a graph is shown with points -3,3 and 7,-3 marked) show function P.

Calc. Average rate of change of p(x) from x=-3 and x=7 (I used the average rate of change formula and came up with - 1 1/2)

Find all numbers "X" such that the average rate of change of p(x) between x=-4 and x=X is zero. (I think I use the DQ Equation here, but I am not sure how exactly)

Find number "Y" so that the average rate of change of p(x) between x=-3 and x=Y is as small as possible. Explain... (No, idea where to start here)
 
Originally posted by: chuckywang
I would help you, but I don't understand the problem.
Click to expand...

can you specify what the "real" problems states exactly.
Then you can add in your stuff about "what you think it asks" or "what i did without problems", etc.

i cant even make out the question from ur description
 
Originally posted by: Tab
I guess my explanation was bad? I'll post it verbatium.

Figure 4 (A secant line on a graph is shown with points -3,3 and 7,-3 marked) show function P.

Calc. Average rate of change of p(x) from x=-3 and x=7 (I used the average rate of change formula and came up with - 1 1/2)

Find all numbers "X" such that the average rate of change of p(x) between x=-4 and x=X is zero. (I think I use the DQ Equation here, but I am not sure how exactly)

Find number "Y" so that the average rate of change of p(x) between x=-3 and x=Y is as small as possible. Explain... (No, idea where to start here)
Click to expand...

answered my post above 🙂
hmm... i dunno the answer though (dont remember doing average rate of change for secant lines) what school/year is this?
 
Originally posted by: Tab
I guess my explanation was bad? I'll post it verbatium.

Figure 4 (A secant line on a graph is shown with points -3,3 and 7,-3 marked) show function P.

Calc. Average rate of change of p(x) from x=-3 and x=7 (I used the average rate of change formula and came up with - 1 1/2)

Find all numbers "X" such that the average rate of change of p(x) between x=-4 and x=X is zero. (I think I use the DQ Equation here, but I am not sure how exactly)

Find number "Y" so that the average rate of change of p(x) between x=-3 and x=Y is as small as possible. Explain... (No, idea where to start here)
Click to expand...

Are you given p(x), or is it just an arbitrary function that goes through points (-3,3) and (7,-3)?
 
what does function p(x) look like?

i would think that the average rate of change for a function p(x) would be zero over a range if the value of p(x) is the same at both ends of the range.
as for finding the smallest possible value, look for a local minimum or maximum by finding a place where the derivative is zero. test if it's a minimum or maximum by calculating p(x) at that point.
 
looking it up, i got the average rate of change as being (delta y)/ (delta x)

(a) average rate of change equals (3+3)/(-3-7)= -3/5

(b) (delta y)/(delta x) = 0, so delta y must equal zero, therefore p(-4) = p(x)

(c) impossible without the function but its fairly easy, like (b), delta y must equal zero so you want the other point where y=3, find the local min or max on the graph
 
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