- Aug 10, 2001
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(1/x^2)*dy/dx = y + (1/x)*y^(2/3)
dy/dx = x^2*y +x*y^(2/3)
dy/dx - x^2*y = x*y^(2/3)
let u = y^(1-n)
u = y^(1/3)
y = u^3
dy/dx = 3*u^2*du/dx
3*u^2*(du/dx) - x^2*u^3 = x*u^2
du/dx - (1/3)*x^2*u = x/3
P(x) = -(1/3)*x^2
(-1/3)*Integral (x^2)dx = (-1/9)*x^3
Integrating factor = e^((-1/9)*x^3))
d/dx[e^((-1/9)*x^3))*u] = (x/3)*e^((-1/9)*x^3))
e^((-1/9)*x^3))*u = Integral [(1/3)*x*e^((-1/9)*x^3))]dx
(1/3)*x*e^((-1/9)*x^3))dx can't be integrated. Did I do something wrong?
dy/dx = x^2*y +x*y^(2/3)
dy/dx - x^2*y = x*y^(2/3)
let u = y^(1-n)
u = y^(1/3)
y = u^3
dy/dx = 3*u^2*du/dx
3*u^2*(du/dx) - x^2*u^3 = x*u^2
du/dx - (1/3)*x^2*u = x/3
P(x) = -(1/3)*x^2
(-1/3)*Integral (x^2)dx = (-1/9)*x^3
Integrating factor = e^((-1/9)*x^3))
d/dx[e^((-1/9)*x^3))*u] = (x/3)*e^((-1/9)*x^3))
e^((-1/9)*x^3))*u = Integral [(1/3)*x*e^((-1/9)*x^3))]dx
(1/3)*x*e^((-1/9)*x^3))dx can't be integrated. Did I do something wrong?
