I know this is the wrong form but I need help with a math problem

[aceofskies05]

link to image of problem link

 

[jman19]

Originally posted by: aceofskies05
link to image of problem link

Well, why don't you show us what you've done so far to try to solve this? Or are you just expecting a handout? :roll:

 

[polarmystery]

Originally posted by: aceofskies05
link to image of problem link

42

 

[aceofskies05]

Well i donno how to start. Like how do you read the problem? from integer 6 to 8 equals 63?

 

[Azndude51]

Originally posted by: jman19

Originally posted by: aceofskies05
link to image of problem link

Well, why don't you show us what you've done so far to try to solve this? Or are you just expecting a handout? :roll:

I agree, people are much more willing to help if they know you actually tried to do the problem.

 

[SmoochyTX]

179/5 or 35.8

 

[invidia]

(h bar * integral of Schroedinger's equation in 8 dimensions in a infinite octobox well) + 3.14

 

[jman19]

Originally posted by: aceofskies05
Well i donno how to start. Like how do you read the problem? from integer 6 to 8 equals 63?

g_6 + g_7 + g_8 = 63

Same idea for the statement on the right.

 

[Schfifty Five]

Originally posted by: aceofskies05
Well i donno how to start. Like how do you read the problem? from integer 6 to 8 equals 63?

Those are summation problems.

There is a function, g(i) and you sum up all the values of g for given i.

For example:

1st one shows i = 6, with 8 on top of the E sign. That means i goes from 6 to 8 inclusive.

g(i) = some function, so come up with a function such that g(6) + g(7) + g(8) = 63.

Just from looking at that, if g(i) = 3*i, then you would get 18+21+24 = 63 which satisfies the first summation. However, that doesn't satisfy the 2nd summation.

 

[aceofskies05]

I dont get how to set it up to solve

 

[aceofskies05]

so would you set the two equations equal to each other?

 

[DrPizza]

Here's an example to describe one way to do this:


Suppose you have the sum from x = 5 to x = 8. Ultimately, you're going to evaluate something for 5, 6, 7, and 8. That's 4 things. That comes into play later.

Let's say that the summation is supposed to equal 100.

You can make up virtually *any* function for inside the summation (for starters.)

Let's say you decided that your function is going to be, simply, x^2.
Well, when you figure out the summation from 5 to 8 of x^2,
you'll have 25 + 36 + 49 + 64. That's 174. You might be thinking, "awww, shit. That didn't work. Back to the drawing board." Not so fast! You're off by 74. And there were 4 things you summed. So, on average, each of them are off by 74/4 or 18.5

So, simply adjust your formula. The sum from i = 5 to 8 of (x^2-18.5)

And, you'll end up with (25 - 18.5) +(36 - 18.5) + (49 - 18.5) + (64 - 18.5)
By the commutative and associative properties, you should see that it's 25 + 36 + 49 + 64 (as before), but you also have -18.5 -18.5 -18.5 -18.5 for a total of minus 74 from the old sum.

Don't stick to something that easy though. It's an open ended question, so make up a sickeningly complicated function so your teacher has lots of fun verifying that it's correct. He'll appreciate it.

 

[aceofskies05]

So I get how to find the solution to one of the summation's, but then how would I set it up to being equal to the other summation?

 

[Saint Michael]

Um, I don't know much about sets, but just intuitively, couldn't you say in a set of { A, B, C, D, E, F, G, H }, where F + G + H = 63,

(A + B + C + D + E + 63)/8 = 63, (A + B + C + D + E + 63)/8 = 152/8, A + B + C + D + E + 63 = 152, A + B + C + D + E = 89.

So any set where the first five values add up to 89 and the last three values add up to 63.

 

[Fenixgoon]

delta(X)*delta(P) = h !

then tell your teacher that he changed the outcome by measuring it </futurama>