How would I figure out the boiling point of water on the surface of Titan?

Itchrelief

Golden Member
Dec 20, 2005
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Originally posted by: Goosemaster
pv / (nr) = t = pv / (nr)

I would think a phase diagram would be a better bet.

Is the ideal gas law directly applicable to this situation? I mean, every liquid does not behave the same as regards to its vaporization.
 

Shawn

Lifer
Apr 20, 2003
32,236
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ok this is how I did it:

T2 = 1 / ( 1/T1 - (R/Hvap x ln(P1/P2)

T2 = 1 / (1/373K - ((8.314 J/mol K / 40.65x10^3 J/mol)(ln 146.7/101.3))
T2 = 384k - 276K = 108C

does that seem right?
 

JEDIYoda

Lifer
Jul 13, 2005
33,986
3,321
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Originally posted by: Shawn
ok this is how I did it:

T2 = 1 / ( 1/T1 - (R/Hvap x ln(P1/P2)

T2 = 1 / (1/373K - ((8.314 J/mol K / 40.65x10^3 J/mol)(ln 146.7/101.3))
T2 = 384k - 276K = 108C

does that seem right?

Very good my young Jedi!
 

iwantanewcomputer

Diamond Member
Apr 4, 2004
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actually, 110.7C. Ideal gas law will give you an approximation at small changes, but not true. P-V-T phase diagrams do not vary linearly. look it up in any standard saturated steam table.
 

Itchrelief

Golden Member
Dec 20, 2005
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Originally posted by: iwantanewcomputer
actually, 110.7C. Ideal gas law will give you an approximation at small changes, but not true. P-V-T phase diagrams do not vary linearly. look it up in any standard saturated steam table.

Yeah, I meant to, um, say what he said, yeah...
Uh huh, yup...

;)